Question

我有以下表格

表：约会

ID | PRICE | PAID
48 |  100  | 180

表：appointmentments_products

ID | APPOINTMENT_ID | PRODUCT_ID | TOTAL
10 |       48       |      1     | 30
11 |       48       |      9     | 30
12 |       48       |      6     | 30

我想以某种方式运行MySQL查询：

a）加入两个表，为每个appointment_id提供约会产品的“TOTAL”，如果“PAID”不等于PRICE（来自约会表）+ TOTAL（来自appointmentments_products表），则显示它。 / p>

这是我到目前为止所做的：

select a.*, b.appointment_id as AppId, b.total as ProdTotal 
from appointments a 
INNER JOIN appointments_products b ON a.id = b.appointment_id

但是这个查询并没有对每个appointment_id的总和进行总结

Answer 1

使用何处检查价格是否等于已付款，使用分组来查看是否已使用appointment_id进行分组。

Answer 2

select a.ID,a.PRICE,a.PAID,a.id as AppId,
       sum(b.total) as ProdTotal 
from appointments a 
INNER JOIN appointments_products b ON a.id = b.appointment_id
group by a.ID,a.PRICE,a.PAID;

Answer 3

选择b.Appointment_Id，a.price，a.PAID，a.id，sum（b.total）AS TotalProd FROM appointmentments_products AS b内部联接约会作为On Appointment_Id = a.Id group by Appointment_Id，a.Price ，a.PAID，a.id有a.PAID！=（a.Price + sum（b.Total））

MySQL内连接和总和两列

3 个答案: