Question

我在angular 5项目中创建了一个管道，它将从html和filter数组中获取输入并返回已过滤的数组。但是目前我正在从HTML文件传递属性名称（＆＃34; firstName＆＃34;）。现在我想要它，它应该从属性过滤＆＃34; firstName＆＃34;和＆＃34; lastName＆＃34;都。请告诉我应该做些什么来做同样的事情？

搜索filter.pipe.ts

import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
    name: 'searchFilter'
})
export class SearchFilter implements PipeTransform {
    transform(data: any, search?: string, propertyName?: string): any {
        if (search === undefined) {
            return data;
        } else {
            return data.filter(obj => obj[propertyName].toLowerCase().includes(search.toLowerCase()));
        }
    }
}

user.component.html

<div class="row" *ngFor="let data of datas| searchFilter: search: 'firstName'}">
   {{data.lastName}}, {{data.firstName}}
</div>

采样data.ts

 datas: [
{ firstName: 'vipin', company: 'abc', lastName: 'sharma' },
{ firstName: 'kevin', company: 'abc2', lastName: 'xyz' },
{ firstName: 'Leos', company: 'abc3', lastName: 'abc' },
]

Answer 1

您可以做的是连接您要搜索的属性：

this.items.map((item) => {
  return {...item, searchTerms: item.firstname + item.lastname;
});

<li *ngFor="let item of items | searchFilter:search:'searchTerms'>{{item.name}}</li>

Answer 2

你能尝试这样吗

 this.data.filter((element: datatype) =>element.firstName && element.lastName)

Answer 3

我得到了答案并且工作正常：

import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
    name: 'searchFilter'
})
export class SearchFilter implements PipeTransform {
    transform(data: any, search?: string, propertyName?: string, propertyName2?: string): any {
        if (search === undefined) {
            return data;
        } else {
            let filteredData = data.filter(obj => obj[propertyName].toLowerCase().includes(search.toLowerCase()));
            if (propertyName2) {
                filteredData = filteredData.concat(data.filter(obj => obj[propertyName2].toLowerCase().includes(search.toLowerCase())));
            }
            return filteredData;
        }
    }
}

如何使用angular中的多个属性过滤数组

3 个答案: