Question

我收到此错误：

TypeError: user_followers() takes exactly 3 arguments (2 given)

在我的python脚本中，运行以下代码行：

origin = api.username_info('edelfilm')
user_id = origin['user']['pk']
followers = []
results = api.user_followers(user_id)

该函数在另一个脚本中定义如下：

    def user_followers(self, user_id, rank_token, **kwargs):
        """
        Get user followers

        :param user_id:
        :param rank_token: Required for paging through a single feed and can be generated with
            :meth:`generate_uuid`. You should use the same rank_token for paging through a single user followers.
        :param kwargs:
            - **query**: Search within the user followers
            - **max_id**: For pagination
        :return:
        """
        raise_if_invalid_rank_token(rank_token)

        endpoint = 'friendships/{user_id!s}/followers/'.format(**{'user_id': user_id})
        query_params = {
            'rank_token': rank_token,
        }
        query_params.update(kwargs)
        res = self._call_api(endpoint, query=query_params)
        if self.auto_patch:
            [ClientCompatPatch.list_user(u, drop_incompat_keys=self.drop_incompat_keys)
             for u in res.get('users', [])]
        return res

我做错了什么？

Answer 1

首先在代码中定义变量rank_token

origin = api.username_info('edelfilm')
user_id = origin['user']['pk']
rank_token = 1 #Assuming it takes an integer value
followers = []

然后将其作为第三个参数传递给您的方法

results = api.user_followers(user_id, rank_token)

TypeError：user_followers（）正好接受3个参数（给定2个）

1 个答案: