Question

我有两张桌子：

Table 1: tracks
id  | artist     | track
---------------------------------------
1     Tom Smith    This Time is Right Time
2     Tom Smith    Oh Yes
3     John Doe     Every Time I See You

Table 2: festival_bands
id  | fest_title | fest_artist
---------------------------------------
1     Hoe Down Fest 2019    John Doe
2     Copperland Fest       Tom Smith
3     Copperland Fest       Reggie Wisk
4     Copperland Fest       Tom Smith
5     Copperland Fest       John Doe
6     Bluegrass Memories    John Doe

对于表2中的每个节日列表，我需要从表1中仅显示一个“曲目”，如下所示：结果：

Copperland Festival:
-----------------------
Tom Smith    This Time is Right Time
John Doe     Every Time I See You

用外行人的话说，逻辑将是：从表1中只获取一个曲目，其中艺术家等于（或匹配）来自表2的fest_artist

我提到了一个类似的问题，它提出了以下方面的建议： $sql="select * from tracks WHERE (artist) in (select fest_artist from festival_bands group by name)"但没有运气。

Answer 1

您可以使用相关子查询为艺术家获取随机曲目：

select fb.*,
       (select t.track
        from tracks t
        where t.artist = fb.fest_artist
        order by t.counter desc
       ) as most_popular_track
from festival_bands fb;

MySQL Query使用来自两个表的数据

1 个答案: