注意:我不确定如何标题,如果有人有更好的想法随时改变它。
我的数据库目前有以下表格(某些列和其他详细信息已从显示的命令输出中删除,但它们不相关):
webserver=> \d+ team
Column | Type | Modifiers | Storage
-------------+------------------------+---------------------------------------------------+----------
id | integer | not null default nextval('team_id_seq'::regclass) | plain
name | character varying(255) | not null | extended
Indexes:
"team_pkey" PRIMARY KEY, btree (id)
"team_name" UNIQUE, btree (name)
Referenced by:
TABLE "challengesolve" CONSTRAINT "challengesolve_team_id_fkey" FOREIGN KEY (team_id) REFERENCES team(id)
webserver=> \d+ challenge
Column | Type | Modifiers | Storage
--------------------+------------------------+--------------------------------------------------------+----------
id | integer | not null default nextval('challenge_id_seq'::regclass) | plain
name | character varying(255) | not null | extended
points | integer | not null | plain
Indexes:
"challenge_pkey" PRIMARY KEY, btree (id)
Referenced by:
TABLE "challengesolve" CONSTRAINT "challengesolve_challenge_id_fkey" FOREIGN KEY (challenge_id) REFERENCES challenge(id)
webserver=> \d+ challengesolve
Column | Type | Modifiers | Storage
--------------+-----------------------------+-----------+---------
team_id | integer | not null | plain
challenge_id | integer | not null | plain
Indexes:
"challengesolve_pkey" PRIMARY KEY, btree (team_id, challenge_id)
"challengesolve_challenge_id" btree (challenge_id)
"challengesolve_team_id" btree (team_id)
Foreign-key constraints:
"challengesolve_challenge_id_fkey" FOREIGN KEY (challenge_id) REFERENCES challenge(id)
"challengesolve_team_id_fkey" FOREIGN KEY (team_id) REFERENCES team(id)
team
和challenge
表应该是相当自我解释的。 challengesolve
表是一个交集表,表明哪些团队已经解决了哪些挑战。
总之,我想找到得分最多的三支球队。我已经知道我可以通过像
这样的声明找到特定团队的积分数SELECT SUM(challenge.points) AS points
FROM challengesolve
INNER JOIN challenge
ON challenge.id = challengesolve.challenge_id
WHERE challengesolve.team_id = 1;
如何修改此查询以找到前三个团队?
答案 0 :(得分:3)
简而言之,我想找到得分最多的三支球队。
您可以使用:
SELECT challengesolve.team_id,SUM(challenge.points) AS points
FROM challengesolve
INNER JOIN challenge
ON challenge.id = challengesolve.challenge_id
GROUP BY challengesolve.team_id
ORDER BY points DESC
LIMIT 3;