Question

我有两个多维数组。第一个包含大量这样的数据：

var dataarray = [ ["AX005A", "Dust / Gas", "1D / 2G", "21", "Ex II 3D IP67"],
["AX007A", "Dust / Gas", "3D / 3G", "22 / 2", "Ex II 3D T60"],
["AX008A", "Dust / Gas", "3D / 3G", "21", "Ex II 3D T60"],
["AX014A", "Dust", "3D", "22", "Ex II 3D T60"],
["AY042A", "Dust", "3D", "20", "Ex II 3D IP65 T65"],
["AY046A", "Dust", "3D", "21", "Ex II 3D T65"]];

第二个包含这样的搜索结果：

var searchterms = [["1","Dust / Gas"],["3","21"]];

现在我想要一个只包含数据的结果数组，其中dataarray与seterterms [n] [0]

给出的正确索引处的每个searchterms匹配

对于上面给出的seachterms，resultarray将是：

resultarray = [["AX005A", "Dust / Gas", "1D / 2G", "21", "Ex II 3D IP67"],
["AX008A", "Dust / Gas", "3D / 3G", "21", "Ex II 3D T60"]];

由于searchterms的数量并不总是相同，因此它必须是一个通用的解决方案，可以使用2个searchterms，就像使用4个或5个searchterms一样。

我尝试使用各种if条件嵌套“for loops”但我在某些时候迷失了：（

如果有人可以提供帮助，我会很棒。我只能使用的框架是jquery（如果这有帮助的话）

Answer 1

第一个解决方案是：

function find(haystack, needles) {
    var results = [];
    for(var i = haystack.length; i--;) {
        var matches = true;
        var item = haystack[i];
        for(var j = needles.length; j--; ) {
            var needle = needles[j];
            if(needle[1] !== item[needle[0]]) {
                matches = false;
                break;
            }
        }
        if(matches) {
            results.push(item);
        }
    }
    return results;
}

DEMO（我认为您的搜索字词必须为["3","21"]，而不是["4","21"] ）

您可以重构代码并使用对象而不是数组（对于find函数不会改变那么多，但更容易创建）。例如。 searchterms可以是对象{0: "Dust / Gas", 3: "21"}，它会将内部for循环更改为

for(var key in needles) {
   if(needles.hasOwnProperty(key)) {
       if(needles[key] !== item[key]) {
           matches = false;
           break;
       }
   }
}

Answer 2

我不得不把我的代码放到，因为你的问题输入错误，我没有工作。 http://jsfiddle.net/cwZz7/3/在此处查看

var dataarray = [ ["AX005A", "Dust / Gas", "1D / 2G", "21", "Ex II 3D IP67"],
["AX007A", "Dust / Gas", "3D / 3G", "22 / 2", "Ex II 3D T60"],
["AX008A", "Dust / Gas", "3D / 3G", "21", "Ex II 3D T60"],
["AX014A", "Dust", "3D", "22", "Ex II 3D T60"],
["AY042A", "Dust", "3D", "20", "Ex II 3D IP65 T65"],
["AY046A", "Dust", "3D", "21", "Ex II 3D T65"]];

var searchterms = [["1","Dust / Gas"],["3","21"]];    
/*
resultarray = [["AX005A", "Dust / Gas", "1D / 2G", "21", "Ex II 3D IP67"],
["AX008A", "Dust / Gas", "3D / 3G", "21", "Ex II 3D T60"]];
*/


var resultArray = new Array();

for(i=0;i< dataarray.length; i++)
{
    var valid = true;
    for(j=0;j < searchterms.length;j++)
    {
          var index = parseInt(searchterms[j][0]);
          if(dataarray[i][index] != searchterms[j][1]){
                 valid = false;
                 break;
          }         

    }
    if(valid == true)
            resultArray.push(dataarray[i]);

}

// resultArray will have your result

在java脚本中比较和过滤多维数组？

2 个答案: