让主线程等到所有线程都完成的最佳方法是什么?
for(int i=0;i<n;i++){ Thread t=new Thread(); t.start(); } //wait for all threads to finish
答案 0 :(得分:18)
创建一个列表并等待所有。
List<Thread> threads = new ArrayList<Thread>();
for(int i=0;i<n;i++){
Thread t=new Thread();
t.start();
threads.add(t);
}
for(Thread t: threads) t.join();
但是,使用ExecutorService可以更好地处理线程池。
ExecutorService es = Executors.newCachedThreadPool();
for(int i=0;i<n;i++)
es.submit(new Task(n));
es.shutdown();
es.awaitTermination(timeout, TimeUnit.SECONDS);
答案 1 :(得分:3)
List<Thread> threads = new ArrayList<Thread>();
for(int i=0;i<n;i++){
Thread t=new Thread();
threads.add(t);
t.start();
}
for(Thread t:threads){
t.join();
}
答案 2 :(得分:1)
可以使用thread.join( )
;来完成。
这里也已经回答了。看一看。
示例:
class MyThread implements Runnable {
String name; // name of thread
Thread t;
MyThread(String threadname) {
name = threadname;
t = new Thread(this, name);
System.out.println("New thread: " + t);
t.start();
}
public void run() {
try {
for (int i = 5; i > 0; i--) {
System.out.println(name + ": " + i);
Thread.sleep(1000);
}
} catch (InterruptedException e) {
System.out.println(name + " interrupted.");
}
System.out.println(name + " exiting.");
}
}
public class MainClass {
public static void main(String args[]) {
MyThread ob1 = new MyThread("One");
MyThread ob2 = new MyThread("Two");
MyThread ob3 = new MyThread("Three");
System.out.println("Thread One is alive: " + ob1.t.isAlive());
System.out.println("Thread Two is alive: " + ob2.t.isAlive());
System.out.println("Thread Three is alive: " + ob3.t.isAlive());
try {
System.out.println("Waiting for threads to finish.");
ob1.t.join();
ob2.t.join();
ob3.t.join();
} catch (InterruptedException e) {
System.out.println("Main thread Interrupted");
}
System.out.println("Thread One is alive: " + ob1.t.isAlive());
System.out.println("Thread Two is alive: " + ob2.t.isAlive());
System.out.println("Thread Three is alive: " + ob3.t.isAlive());
System.out.println("Main thread exiting.");
}
}
虽然问题标记在“java”下,但也可以通过以下方式在C#中完成
答案 3 :(得分:0)
我认为根据您的要求,最佳解决方案是 CyclicBarrier 看看http://download.oracle.com/javase/1.5.0/docs/api/java/util/concurrent/CyclicBarrier.html
或
答案 4 :(得分:0)
您可以使用CountDOwnLatch
CountDownLatch lat = new CountDownLatch(noOfTasks);
ExecutorService exec = Executors.newFixedThreadPool(4);
while(...) {
exec.execute(new MyTask());
}
try {
lat.await();
}
catch (InterruptedException E) {
//
}
并在你的任务中 (附在try / finally中)
lat.countDown();