基于列表中的日期字段,在每一天对使用XSLT 1.0的列表进行分组

时间:2018-06-02 11:20:57

标签: sorting xslt grouping

我将以下XML作为示例,并希望得到此结果:

20.06.2016
    08:30-09:00   TEST_PHX_88
    09:30-10:00   TEST_PHX_99
21.06.2016
    10:30-11:30   TEST_PHX_66
23.06.2018
    09:30-10:00   TEST_PHX_77
    09:30-10:30   TEST_PHX_55

因此,列表应按天分组,并按日期内的时间排序

有人可以提供XSL 1.0示例来执行此操作吗?

很多Thx! 劳伦

<XML_DATA>
    <GROUPID>1</GROUPID>
    <SRO_IF_POLYTERMINE_PRO_PATIENT>
      <XRO_PATNAME>TEST_PHX_99</XRO_PATNAME>
      <TRMBEGIN_Q>20.06.2018 09:30:00</TRMBEGIN_Q>
      <TRMENDE_Q>20.06.2018 10:00:00</TRMENDE_Q>
    </SRO_IF_POLYTERMINE_PRO_PATIENT>
    <SRO_IF_POLYTERMINE_PRO_PATIENT>
      <XRO_PATNAME>TEST_PHX_88</XRO_PATNAME>
      <TRMBEGIN_Q>20.06.2018 08:30:00</TRMBEGIN_Q>
      <TRMENDE_Q>20.06.2018 09:00:00</TRMENDE_Q>
    </SRO_IF_POLYTERMINE_PRO_PATIENT>
    <SRO_IF_POLYTERMINE_PRO_PATIENT>
      <XRO_PATNAME>TEST_PHX_77</XRO_PATNAME>
      <TRMBEGIN_Q>23.06.2018 09:30:00</TRMBEGIN_Q>
      <TRMENDE_Q>23.06.2018 10:00:00</TRMENDE_Q>
    </SRO_IF_POLYTERMINE_PRO_PATIENT>
    <SRO_IF_POLYTERMINE_PRO_PATIENT>
      <XRO_PATNAME>TEST_PHX_66</XRO_PATNAME>
      <TRMBEGIN_Q>21.06.2018 10:30:00</TRMBEGIN_Q>
      <TRMENDE_Q>21.06.2018 11:30:00</TRMENDE_Q>
    </SRO_IF_POLYTERMINE_PRO_PATIENT>
    <SRO_IF_POLYTERMINE_PRO_PATIENT>
      <XRO_PATNAME>TEST_PHX_55</XRO_PATNAME>
      <TRMBEGIN_Q>23.06.2018 09:30:00</TRMBEGIN_Q>
      <TRMENDE_Q>23.06.2018 10:30:00</TRMENDE_Q>
    </SRO_IF_POLYTERMINE_PRO_PATIENT>
</XML_DATA>

1 个答案:

答案 0 :(得分:1)

由于您使用的是XSLT 1.0,因此必须使用名为Muenchian Grouping的技术。

对于此要求,将定义一个复合键,其中包含元素date<TRMBEGIN_Q>字符串的<TRMENDE_Q>部分。

<xsl:key name="keyDate" match="SRO_IF_POLYTERMINE_PRO_PATIENT" use="concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10))" />

接下来,为分组元素运行for-each循环,在此分组中,元素在复合键上排序,以便21.06.2018出现在23.06.2018之前。

<xsl:for-each select="SRO_IF_POLYTERMINE_PRO_PATIENT[generate-id() = generate-id(key('keyDate',concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10)))[1])]">
    <xsl:sort select="substring(key('keyDate', concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10)))/TRMBEGIN_Q, 1, 10)" />
    ....
</xsl:for-each>

最后一步是在key内循环,以提取组内元素的各个值。在此循环中,已应用time部分的排序。

<xsl:for-each select="key('keyDate', concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10)))">
    <xsl:sort select="substring(TRMBEGIN_Q, 12, 5)" />
    ....
</xsl:for-each>

以下是完整的XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="html" />
    <xsl:strip-space elements="*" />

    <xsl:key name="keyDate" match="SRO_IF_POLYTERMINE_PRO_PATIENT" use="concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10))" />

    <xsl:template match="XML_DATA">
        <table border="0" cellspacing="0" cellpadding="5">
            <xsl:for-each select="SRO_IF_POLYTERMINE_PRO_PATIENT[generate-id() = generate-id(key('keyDate',concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10)))[1])]">
                <xsl:sort select="substring(key('keyDate', concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10)))/TRMBEGIN_Q, 1, 10)" />
                <tr>
                    <td colspan="2">
                        <b><xsl:value-of select="substring(key('keyDate', concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10)))/TRMBEGIN_Q, 1, 10)" /></b>
                    </td>
                </tr>
                <xsl:for-each select="key('keyDate', concat(substring(TRMBEGIN_Q, 1, 10), '|', substring(TRMENDE_Q, 1, 10)))">
                    <xsl:sort select="substring(TRMBEGIN_Q, 12, 5)" />
                    <tr>
                        <td><xsl:value-of select="concat(substring(TRMBEGIN_Q, 12, 5), ' - ', substring(TRMENDE_Q, 12, 5))" /></td>
                        <td><xsl:value-of select="XRO_PATNAME" /></td>
                    </tr>
                </xsl:for-each>
            </xsl:for-each>
        </table>
    </xsl:template>
</xsl:stylesheet>

这将生成一个HTML表格,如下所示。

Output HTML Table