我是JavaFx的新手。我已经设计了一个桌子现场建造者,在第1列我有一个按钮,在第2列我有一个复选框。单击按钮时,我想获取checkbox属性。但问题是我总是把输出作为假。这是我的代码
Model.java
private boolean Active;
public boolean isActive() {
return Active;
}
public void setActive(boolean active) {
Active = active;
}
在我的控制器类中,我设计了下面的initialize()方法
Controller.java
@FXML
private TableView<Model> tableBuilding;
@FXML
private TableColumn<Model,Boolean> colActive;
@FXML
private TableColumn<Model,Model> colAction;
@Override
public void initialize(URL arg0, ResourceBundle arg1) {
//Containing the button
colAction.setCellFactory(col -> {
Button ShowButton = new Button("Show");
TableCell<Model, Model> cell = new TableCell<Model, Model>() {
@Override
//Updating with the number of row
public void updateItem(Model building, boolean empty) {
super.updateItem(building, empty);
if (empty) {
setGraphic(null);
} else {
setGraphic(ShowButton);
}
}
};
ShowButton.setOnAction(event -> {
TableRow row = cell.getTableRow();
Model building=(Model) row.getItem();
ObservableList<Model> data = tableBuilding.getItems();
for (Model item : data){
//check the boolean value of each item to determine checkbox state
System.out.println(item.isActive());
}
});
return cell ;
});
//Containing the checkbox
colActive.setCellValueFactory(new PropertyValueFactory<Model,Boolean>("Active"));
colActive.setCellFactory(tc -> new CheckBoxTableCell<>());
}
此处System.out.println(item.isActive());
始终以输出形式重新调整为false。如何获取该复选框的实际属性?有人可以帮帮我吗?
答案 0 :(得分:0)
我相信你可以稍微简化你的控制器。尝试将控制器代码更改为:
public class Controller {
@FXML
private TableView<Model> tableBuilding;
@FXML
private TableColumn<Model, Boolean> colActive;
@FXML
private TableColumn<Model, Model> colAction;
@FXML
public void initialize() {
// Sample List
ObservableList<Model> models = FXCollections.observableArrayList();
models.addAll(
new Model(),
new Model(),
new Model()
);
tableBuilding.setItems(models);
//Containing the button
colAction.setCellFactory(col -> {
Button ShowButton = new Button("Show");
TableCell<Model, Model> cell = new TableCell<>() {
@Override
//Updating with the number of row
public void updateItem(Model building, boolean empty) {
super.updateItem(building, empty);
if (empty) {
setGraphic(null);
} else {
setGraphic(ShowButton);
}
}
};
ShowButton.setOnAction(event -> {
TableRow row = cell.getTableRow();
Model building = (Model) row.getItem();
System.out.println(building.getActive());
});
return cell;
});
//Containing the checkbox
colActive.setCellValueFactory(new PropertyValueFactory<>("active"));
colActive.setCellFactory(col -> new CheckBoxTableCell<>());
}
}
具体来说,最后两行代码;您不需要指定自己的TableCell
,因为CheckBoxTableCell
会自行处理Model
的更新。
但是,需要更改Model
类以将Active
字段更新为true属性;否则,TableView
无法正确更新。控制器colActive.setCellValueFactory(new PropertyValueFactory<Model,Boolean>("Active"));
中的行告诉单元格的值绑定到名为Model
的{{1}}类中的JavaFX属性,但是没有这样的属性。
以下是定义属性的正确方法:
Active
有趣的是,这似乎是遵循正确的Java编码实践很重要的一种情况。 public class Model {
private SimpleBooleanProperty active = new SimpleBooleanProperty(true);
public boolean getActive() {
return active.get();
}
public SimpleBooleanProperty activeProperty() {
return active;
}
public void setActive(boolean active) {
this.active.set(active);
}
}
属性在这里也应该是小写的,不是大写的。