Question

我有2个对象数组，我想合并它们。

var fruits = [
    {name: 'pear', cultivar: '', color: 'yellowgreen', size: '6'},
    {name: 'apple', cultivar: 'Annurca', color: 'red', size: '5'},
    {name: 'apple', cultivar: 'fuji', color: 'red', size: '4'}
]; 

var quantity = [
    {name: 'pear', number: '15'},
    {name: 'apple', number: '50', scad: '2018'},
    {name: 'apple', number: '50'}
];

我想要的是：

var all = [
    {name: 'pear', cultivar: '', color: 'yellowgreen', size: '6', number: '15', scad: 'NaN'},
    {name: 'apple', cultivar: 'Annurca', color: 'red', size: '5', number: '50', scad: '2018'},
    {name: 'apple', cultivar: 'fuji', color: 'red', size: '4', number: '50', scad: 'NaN'}
];

每个元素都包含所有属性： name ， cultivar ， color ， size ，数字和 scad （如果财产不存在，则为NaN。）

Answer 1

只需.map阵列：

＆＃13;

var fruits = [
    {name: 'pear', cultivar: '', color: 'yellowgreen', size: '6'},
    {name: 'apple', cultivar: 'Annurca', color: 'red', size: '5'},
    {name: 'apple', cultivar: 'fuji', color: 'red', size: '4'}
]; 

var quantity = [
    {name: 'pear', number: '15'},
    {name: 'apple', number: '50', scad: '2018'},
    {name: 'apple', number: '50'}
];

const all = fruits.map((fruit, i) => (
  { ...fruit, scad: NaN, ...quantity[i] }
));
console.log(all);

＆＃13;

合并管理所有属性的对象数组

1 个答案: