Question

StringRequest stringRequest=new StringRequest(Request.Method.POST,url, new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {
                Toast.makeText(LoginActivity.this, "Success", Toast.LENGTH_SHORT).show();
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                Toast.makeText(LoginActivity.this, "Check Again", Toast.LENGTH_SHORT).show();
                //Toast.makeText(LoginActivity.this, error.toString(), Toast.LENGTH_SHORT).show();
                NetworkResponse response = error.networkResponse;
                if (error instanceof ServerError && response != null) {
                    try {
                        String res = new String(response.data,
                                HttpHeaderParser.parseCharset(response.headers, "utf-8"));
                        // Now you can use any deserializer to make sense of data
                        Toast.makeText(LoginActivity.this, res, Toast.LENGTH_SHORT).show();
                        Log.i("Error Code",res);
                    } catch (UnsupportedEncodingException e1) {
                        // Couldn't properly decode data to string
                        e1.printStackTrace();
                    }
                }
            }
        }){
            @Override
            public Map<String, String> getHeaders() throws AuthFailureError {
                HashMap<String, String> headers = new HashMap<String, String>();
                headers.put("X-Api-Key",APIKey);
                //headers.put("Content-Type", "application/json; charset=utf-8");
                return headers;
            }

            @Override
            protected Map<String,String> getParams() throws AuthFailureError{
                Map<String, String> params = new HashMap<String, String>();
                params.put("email",email);
                params.put("password",password);
                //params.put("grant_type", "password");
                return params;
            }

        };
        MySingleton.getmInstance(LoginActivity.this).addToRequestQueue(stringRequest);

我尝试在postman中使用相同的标题和参数传递相同的url，url在那里工作得很好。如您所见，我已应用了类似问题中提供的所有更正。生成的错误代码为：

<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
    <html><head>
    <title>400 Bad Request</title>
    </head><body>
    <h1>Bad Request</h1>
    <p>Your browser sent a request that this server could not understand.<br />
    </p>
    </body></html>

我也尝试使用相同的代码命中其他api，它们工作得很好。但这个api我不能打，但正如我在Postman中所说，我可以正确地击中它。

Android Volley - BasicNetwork.performRequest：用于访问网址的意外响应代码400

0 个答案: