我在后端使用spring-boot,我尝试使用smtp向gmail帐户发送电子邮件,但我正在解决一些错误。
以下是此tutorial之后的代码:
application.properties:
spring.mail.host=smtp.gmail.com
spring.mail.port=587
spring.mail.username=xxx@gmail.com
spring.mail.password=xxxpwd
spring.mail.properties.mail.smtp.auth=true
spring.mail.properties.mail.smtp.starttls.enable=true
Class MailObject.java:
package interv.Web.Notifications;
import org.hibernate.validator.constraints.Email;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;
public class MailObject {
@Email
@NotNull
@Size(min = 1, message = "Please, set an email address to send the message to it")
private String to;
private String subject;
private String text;
public String getTo() {
return to;
}
public void setTo(String to) {
this.to = to;
}
public String getSubject() {
return subject;
}
public void setSubject(String subject) {
this.subject = subject;
}
public String getText() {
return text;
}
public void setText(String text) {
this.text = text;
}
}
MailController.java:
@Controller
public class MailController {
@Autowired
public EmailServiceImpl emailService;
@Autowired
public SimpleMailMessage template;
@RequestMapping(value = "/send", method = RequestMethod.POST)
public String createMail(@RequestBody MailObject mailObject) {
emailService.sendSimpleMessage(mailObject.getTo(),
mailObject.getSubject(), mailObject.getText());
return "that was succesfull";
}
}
EmailService.java
public interface EmailService {
void sendSimpleMessage(String to,
String subject,
String text);
void sendSimpleMessageUsingTemplate(String to,
String subject,
SimpleMailMessage template,
String templateArgs);
}
EmailServiceImpl.java
@Component
public class EmailServiceImpl implements EmailService{
@Autowired
public JavaMailSender emailSender;
@Override
public void sendSimpleMessage(String to, String subject, String text) {
SimpleMailMessage message = new SimpleMailMessage();
message.setTo(to);
message.setSubject(subject);
message.setText(text);
emailSender.send(message);
}
@Override
public void sendSimpleMessageUsingTemplate(String to, String subject, SimpleMailMessage template, String templateArgs) {
String text = String.format(template.getText(), templateArgs);
sendSimpleMessage(to, subject, text);
}
}
在运行时我在控制台中没有错误,但是当我尝试发送电子邮件时,我收到此错误:
servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.mail.MailSendException: Mail server connection failed; nested exception is javax.mail.MessagingException: Could not convert socket to TLS;
nested exception is:
javax.net.ssl.SSLHandshakeException: sun.security.validator.ValidatorException: PKIX path building failed: sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target. Failed messages: javax.mail.MessagingException: Could not convert socket to TLS;
nested exception is:
javax.net.ssl.SSLHandshakeException: sun.security.validator.ValidatorException: PKIX path building failed: sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target; message exceptions (1) are:
Failed message 1: javax.mail.MessagingException: Could not convert socket to TLS;
nested exception is:
javax.net.ssl.SSLHandshakeException: sun.security.validator.ValidatorException: PKIX path building failed: sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target] with root cause
sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target
at sun.security.provider.certpath.SunCertPathBuilder.build(SunCertPathBuilder.java:141) ~[na:1.8.0_161]
at sun.security.provider.certpath.SunCertPathBuilder.engineBuild(SunCertPathBuilder.java:126) ~[na:1.8.0_161]
at java.security.cert.CertPathBuilder.build(CertPathBuilder.java:280) ~[na:1.8.0_161]
我不明白为什么我会收到这个错误:任何想法?
答案 0 :(得分:1)
我认为原因是出于安全原因,Gmail会默认阻止访问安全性较低的应用 检查这个类似的问题它的答案可能对你有帮助 Error sending email with gmail
答案 1 :(得分:0)
错误清楚地显示'UnknownHost'。检查您的应用是否可以访问互联网并且能够解析该名称。