我有一个方法,我正在执行curl命令并返回结果。我想将参数传递给此方法,但它无法正常工作。
commande_mine() {
local MY_OUTPUT=$(curl -X POST \
http://localhost:5000/myapp \
-H 'cache-control: no-cache' \
-H 'content-type: application/json' \
-d '{
"filepath": "$1"
}')
echo $MY_OUTPUT
}
for f in "/Users/anthony/my files"/*
do
commande_mine $f >> test.txt
break # break first time until everything works as expected
done
如何使用$f
命令中传递给函数的curl
参数?
答案 0 :(得分:1)
您可以使用:
commande_mine() {
local MY_OUTPUT=$(curl -X POST \
http://localhost:5000/myapp \
-H 'cache-control: no-cache' \
-H 'content-type: application/json' \
-d '{
"filepath": "'"$1"'"
}')
echo "$MY_OUTPUT"
}
并将其命名为:
for f in "/Users/anthony/my files"/*
do
commande_mine "$f"
break
done > test.txt