Question

我有一个表，其中包含用于存储服务开始时间和结束时间的列（我没有日期和时间，只有一周中的某一天）。考虑到服务周一开始，周二结束，我必须检查一周是否有时间。有人能帮助我吗？

CREATE TABLE #Calendar (
    Name VARCHAR(100),
    DayWeek INT,
    HourStart TIME,
    HourEnd TIME
);

INSERT INTO #Calendar (Name, DayWeek, HourStart, HourEnd)
    VALUES ('Make a Cake', 1, '19:00:00', '07:00:00');

INSERT INTO #Calendar (Name, DayWeek, HourStart, HourEnd)
    VALUES ('Make a cookie', 1, '07:00:00', '19:00:00');

INSERT INTO #Calendar (Name, DayWeek, HourStart, HourEnd)
    VALUES ('Make a cookie', 2, '19:00:00', '23:00:00');

Answer 1

好的，这必须有效。它显示每一行都有时间冲突;如果你取消注释它将显示没有冲突的行的最后一个

declare @test_DateTimeStart datetime=dateadd(day,4,'20:00:00') -- Check from Monday 20:00
declare @test_DateTimeEnd datetime=dateadd(day,5,'20:00:00') -- Check to Tuesday 20:00

select q2.result,c.*
from 
    #Calendar c
    cross apply 
    (   select 
        dateadd(day,DayWeek,convert(datetime,HourStart)) as DateTimeStart,
        dateadd(day,DayWeek+1,convert(datetime,HourEnd)) as DateTimeEnd
    )q
    cross apply (select
        case when exists
        (
            select 1 from #Calendar c2 where 
                (@test_DateTimeStart>DateTimeStart and @test_DateTimeStart<DateTimeEnd)
                or
                (@test_DateTimeEnd  >DateTimeStart and @test_DateTimeEnd  <DateTimeEnd)
        )
        then 'Time is taken due to this row -->'
        else 'Time is free due to this row -->'
        end as result
    )q2
--where result='Time is taken due to this row -->'

Answer 2

这将解决它。它将无法使用索引，因为它在比较时使用列计算：

DECLARE @from time = '22:59', @to time = '23:01'

DECLARE @DayWeek int = 2

;WITH CTE as
(
SELECT 
  dateadd(d, @DayWeek, cast(@from as datetime)) startdate,
  dateadd(d, 
    CASE WHEN @to < @from 
         THEN @DayWeek + 1
         ELSE @DayWeek
    END,
  cast(@to as datetime)) enddate
)
SELECT CASE WHEN 
not exists
(
  SELECT * 
  FROM #Calendar c 
  WHERE cte.startdate < dateadd(d, CASE WHEN HourEnd < HourStart 
  THEN DayWeek + 1 ELSE DayWeek END, cast(HourEnd as datetime))
  AND cte.enddate > dateadd(d, DayWeek, cast(HourEnd as datetime))
) THEN 'Available' ELSE 'Not available' END
FROM CTE

Answer 3

使用以下代码获取当天的实时日期。然后与您的保存数据进行比较

var myHttpWebRequest = (HttpWebRequest)WebRequest.Create("http://www.google.com");

var response = myHttpWebRequest.GetResponse();

string todaysDates = response.Headers["date"];

return  DateTime.ParseExact(todaysDates,"ddd, dd MMM yyyy HH:mm:ss'GMT'",CultureInfo.InvariantCulture.DateTimeFormat,DateTimeStyles.AssumeUniversal).DayOfWeek;

检查tsql中从一天到另一天的小时数

3 个答案: