Question

我正在尝试创建一个删除不在DB中的图像的脚本

我的代码（已更新）：我有一个问题：

类似语法like '%$f%'

#!/bin/bash

db="intranet_carc_development"
user="benjamin"

for f in public/uploads/files/*
do
  if [[ -f "$f" ]]
  then
    psql $db $user -t -v "ON_ERROR_STOP=1" \
    -c 'select * from public.articles where content like "%'"$(basename "$f")"'%"' | grep . \
    && echo "exist" \
    || echo "doesn't exist"
  fi
done

我有以下错误：

ERROR:  column "%1YOLV3M4-VFb2Hydb0VFMw.png%" does not exist
LINE 1: select * from public.articles where content like "%1YOLV3M4-...
                                                         ^
doesn't exist
ERROR:  column "%wnj8EEd8wuJp4TdUwqrJtA.png%" does not exist
LINE 1: select * from public.articles where content like "%wnj8EEd8w...

编辑：如果我对\'%$f%\'使用like：

/purge_files.sh: line 12: unexpected EOF while looking for matching `"'
./purge_files.sh: line 16: syntax error: unexpected end of file

Answer 1

您的代码存在以下问题：

$ f是public / uploads / files / FILENAME，我只想要FILENAME

您可以使用basename来规避：

f="$(basename "$f")"
psql $db $user -c "select * from public.articles where content like '%$f%'"...

（如果你的文件名中有空格和特殊字符，这里的额外引号可以防止出现问题）

您的psql请求将始终返回true even if no rows are found
即使请求失败，您的psql命令也会返回true，除非您set the variable 'ON_ERROR_STOP' to 1

如链接问题所示，您可以使用以下语法：

#!/bin/bash

set -o pipefail #needed because of the pipe to grep later on

db="intranet_carc_development"
user="benjamin"

for f in public/uploads/files/*
do
  if [[ -f "$f" ]]
  then
    f="$(basename "$f")"
    psql $db $user -t -v "ON_ERROR_STOP=1" \
    -c "select * from public.articles where content like '%$f%'" | grep . \
    && echo "exist" \
    || echo "doesn't exist"
  fi
done

Bash清除脚本

1 个答案: