请考虑以下代码:
$capability = new ClientToken($TWILIO_ACCOUNT_SID, $TWILIO_AUTH_TOKEN);
$capability->allowClientOutgoing($TWILIO_TWIML_APP_SID);
$capability->allowClientIncoming($identity); //what to do in this?..
$token = $capability->generateToken();
此代码的行为是,在我按下“按钮”之后。按钮,它打印:
from kivy.app import App
from kivy.uix.boxlayout import BoxLayout
from kivy.uix.button import Button
class First(BoxLayout):
def __init__(self, **kwargs):
super().__init__(**kwargs)
x = Button(text='somebutton')
x.bind(on_press=lambda*_: print('First press'))
x.bind(on_press=lambda*_: print('Second press'))
self.add_widget(x)
def something(self, *somethingishereignored):
print("I have something")
class FChooser(App):
def build(self):
return First()
if __name__ == '__main__':
FChooser().run()
所以,我用Google搜索并发现我应该使用unbind()函数,并添加了这个:
Second press
First press
但输出没有变化。它仍然是相同的输出。我如何发布绑定?这只是一个最小的例子,我打算使用这个功能动态地将函数绑定和取消绑定到一个按钮,以便为同一个按钮添加各种功能。
答案 0 :(得分:1)
该函数不会解除绑定,因为您没有引用绑定的函数。当您使用内联lambda时,该方法引用未保存,因此您以后不能使用它来取消绑定 这将工作:
from kivy.app import App
from kivy.uix.boxlayout import BoxLayout
from kivy.uix.button import Button
class First(BoxLayout):
def __init__(self, **kwargs):
super().__init__(**kwargs)
x = Button(text='somebutton')
x.bind(on_press=self.press1)
x.unbind(on_press=self.press1)
x.bind(on_press=self.press2)
self.add_widget(x)
def press1(self, *args):
print("First press")
def press2(self, *args):
print("Second press")
class FChooser(App):
def build(self):
return First()
if __name__ == '__main__':
FChooser().run()
或者这个:
press1 = lambda*_: print('First press')
press2 = lambda*_: print('Second press')
x = Button(text='somebutton')
x.bind(on_press=press1)
x.unbind(on_press=press1)
x.bind(on_press=press2)