Question

以下[key：value]对，不适合使用

A_Geo：“MULTIPOINT（（121.5831587 24.9971109））”

我需要支持将其转换为字典并像其他对一样组合成字典数组

[_id：1，.....，lng：121.5831587，lat：24.9971109，......]

为了解析以下JSON以将Geo数据分析为lng和lat，我们尝试应用JSONSerialization。但不想进一步。

result: 
{
        offset: 0,
        limit: 10000,
        results:[
     -{
        _id: "1",
        A_Name_Ch: “Great Hotel Spot",
        A_Geo: "MULTIPOINT ((121.5831587 24.9971109))",
        A_Location: “Great Spot",
        A_Name_En: "Giant Great",
        A_CID: "1"
    }, {…}, {…}
    }

    ]
}

let ArticlesUrl = URL (string: "http://data.taipei/opendata/datalist/apiAccess?scope=resourceAquire&rid=a3e2b221-75e0-45c1-8f97-75acbd43d613")!
let session = URLSession.shared
    let task = session.dataTask(with: ArticlesUrl){(data,response,error) in
        if let error = error {
            print ("failed!!")
            completionHandler(nil,error)
            return
        }
        let data = data!

        if let jsonObject = try? JSONSerialization.jsonObject(with: data, options: .mutableContainers) as![String:[String: Any]], let articleArray = jsonObject["result"]!["results"] as? [[String: Any]]{

            var articles = [Article]()
            for articleDict in articleArray{
                let article = Article(rawData: articleDict)
                articles.append(article)
            }
            completionHandler(articles, nil)
        }
    }
    task.resume()

Answer 1

您无法与lat and lng结合使用，您必须在解析时手动执行此操作。

这是给您的信息。假设你已经解析了A_Geo值，现在你有了跟随字符串"MULTIPOINT ((121.5831587 24.9971109))"，你应该这样做，

let string = "MULTIPOINT ((121.5831587 24.9971109))"
let value = string.slice(from: "((", to: "))")
let latitude = value?.components(separatedBy: " ").first
let longitude = value?.components(separatedBy: " ").last

print(latitude!, longitude!)

输出将是，

("121.5831587") ("24.9971109")

以下是slice的{{1}}泛型函数。

String extension

extension String { func slice(from: String, to: String) -> String? { return (range(of: from)?.upperBound).flatMap { substringFrom in (range(of: to, range: substringFrom..<endIndex)?.lowerBound).map { substringTo in String(self[substringFrom..<substringTo]) } } } }是通用函数，只要有这种情况，就可以在整个应用程序的任何地方使用它。

Answer 2

解析MULTIPOINT字符串表达式的替代方法是Scanner

let string = "MULTIPOINT ((121.5831587 24.9971109))"
let scanner = Scanner(string: string)
var lat = 0.0, lng = 0.0
if scanner.scanUpToCharacters(from: CharacterSet.decimalDigits, into: nil) {
    scanner.scanDouble(&lat)
    scanner.scanDouble(&lng)
}
let coordinate = ["lat" : lat, "lng" : lng]

Answer 3

参考上面的评论和相关文章，我在Swift 4中找到了一个解决方案，尽管这个解决方案很有效。如果有人能够改进它，我将非常感激。

if let geo = article.geo {
                print("Geo is \(geo)") 
               // geo = "MULTIPOINT ((121.5831587 24.9971109))"

                let geo_StringA = geo.split(separator: "(", maxSplits: 3)[1]
                let geo_StringB = geo_StringA.split(separator: ")", maxSplits: 3)[0]
                let geo_array = geo_StringB.split(separator: " ", maxSplits: 3)

                let lng_String = String(geo_array.first!) as NSString
                let lng = lng_String.doubleValue
                self.articles[indexPath.row].lng = lng
                print("lng is \(lng)")

                let lat_String = String(geo_array.last!) as NSString
                let lat = lat_String.doubleValue
                self.articles[indexPath.row].lat = lat
                print("lat is \(lat)")
            }

JSON数据：A_Geo：“MULTIPOINT（（121.5831587 24.9971109））”需要解析为字典

3 个答案: