我有两个不同的结构,其中following
是链表的节点
typedef struct following{
char nick[6];
int last_message;
bool first_time;
struct following *next;
}following;
typedef struct user{
char nick[6];
char name[26];
int n_messages;
int n_following;
int n_followers;
following *arr_following;
following *arr_unfollowed;
}user;
我必须通过读取这样的文件来填充user
结构:
zsq4r Pseu Donym 3 1 2;zero7 2 true!
zero7 James Bond 4 3 3;zsq4r 3 true!zero7 4 false!MrPym 1 true!
MrPym A Perfect Spy 1 3 1;zsq4r 3 true!zero7 4 true!AlecS 1 true!
AlecS He Who Came from the Cold 1 0 1;
由";"分隔的内容是填充user
结构和由"!"分隔的内容。填写following
结构。
注意:"秒"文件每行的元素将是用户的名称,最多可以有25个字符,可以用空格分隔。例如,"来自寒冷的他"是一个有效的名字。
我试着像这样填写:
void read_from_file(hashtable *active_users, FILE *fp_active){
const char *delimiter1 = "!";
const char *delimiter2 = ";";
char *last_token;
char buffer[1540];
while(fgets(buffer, 1540, fp_active)) {
user *new_user = malloc(sizeof(user));
last_token = strtok( buffer, delimiter2);
while( last_token != NULL ){
sscanf(last_token,"%s %[^\n] %d %d %d", new_user->nick, new_user->name, &new_user->n_messages, &new_user->n_following,
&new_user->n_followers);
last_token = strtok( NULL, delimiter1);
}
insert(active_users, new_user);
}
}
虽然" last_token"变量在每个循环中保存从文件中读取的字符串的正确部分,我无法找到填充两个结构,因为sscanf
只填充user
结构的一部分。 / p>
任何帮助都将不胜感激。
答案 0 :(得分:0)
根据我设法解决问题的评论提示,将文件的方面更改为:
zero7;James Bond;2;1;0[MrPym;1;true](zero7;0;false)
MrPym;A Perfect Spy;1;0;1
zsq4r;Pseu Donym;3;1;2[zero7;2;true]
zero7;James Bond;4;3;3[zsq4r;3;true][zero7;3;false][MrPym;1;true]
MrPym;A Perfect Spy;1;3;1[zsq4r;3;true][zero7;4;true][AlecS;1;true]
AlecS;He Who Came from the Cold;1;0;1
从那时起,我使用以下代码将信息提取到不同的结构:
void read_from_file(hashtable *active_users, hashtable *inactive_users, FILE *fp_active, FILE *fp_inactive){
char m_bool[6];
char *first_token;
char *last_token;
char buffer[1540];
char buffer2[1540];
while(fgets(buffer, 1540, fp_active)) {
strcpy(buffer2, buffer);
user *new_user = malloc(sizeof(user));
new_user->arr_following = NULL;
new_user->arr_unfollowed = NULL;
last_token = strtok( buffer, "[");
sscanf(last_token,"%[^;]; %[^;]; %d; %d; %d", new_user->nick, new_user->name, &new_user->n_messages, &new_user->n_following,
&new_user->n_followers);
last_token = strtok( NULL, "[");
while(last_token != NULL){
following *tmp_following = malloc(sizeof(following));
sscanf(last_token," %[^;]; %d; %5s", tmp_following->nick, &tmp_following->last_message, m_bool);
if(strcmp(m_bool, "true]") == 0)
add(&new_user->arr_following, tmp_following->nick, tmp_following->last_message, true);
else
add(&new_user->arr_following, tmp_following->nick, tmp_following->last_message, false);
last_token = strtok( NULL, "[");
}
first_token = strtok( buffer2, ")");
while(first_token != NULL && strcmp(first_token, buffer2) != 0){
following *tmp_following = malloc(sizeof(following));
sscanf(first_token," %[^;]; %d; %5s", tmp_following->nick, &tmp_following->last_message, m_bool);
if(strcmp(m_bool, "true]") == 0)
add(&new_user->arr_unfollowed, tmp_following->nick, tmp_following->last_message, true);
else
add(&new_user->arr_unfollowed, tmp_following->nick, tmp_following->last_message, false);
first_token = strtok( NULL, "(");
}
insert2(active_users, new_user);
}
}
我必须为每一行重新运行文件字符串2次,因为有3种类型的令牌,; [ (