我手边有一个正则表达式任务,可以真正使用一些帮助。
说我有如下文字:
To Sherlock Holmes she is always <i>THE</i> woman.
我需要将每个字符都包含在span标记中,HTML标记除外。例如,上面的文字将是:
<span>T</span><span>o</span><span> </span><span>S</span><span>h</span>
<span>e</span><span>r</span><span>l</span><span>o</span><span>c</span>
<span>k</span><span> </span><span>H</span><span>o</span><span>l</span>
<span>m</span><span>e</span><span>s</span><span> </span><span>s</span>
<span>h</span><span>e</span><span> </span><span>i</span><span>s</span>
<span> </span><span>a</span><span>l</span><span>w</span><span>a</span>
<span>y</span><span>s</span><span> </span><i><span>T</span><span>H</span>
<span>E</span></i><span> </span><span>w</span><span>o</span><span>m</span>
<span>a</span><span>n</span><span>.</span>
请注意:
<i></i>
不是欢迎任何建议。
谢谢!
答案 0 :(得分:4)
DOM交互可以更好地处理这项工作。以下两个实用程序函数将帮助使用span标记包装给定文本中的每个字符。
/**
* recursively get all text nodes as an array for a given element
*/
function getTextNodes(node) {
var childTextNodes = [];
if (!node.hasChildNodes()) {
return;
}
var childNodes = node.childNodes;
for (var i = 0; i < childNodes.length; i++) {
if (childNodes[i].nodeType == Node.TEXT_NODE) {
childTextNodes.push(childNodes[i]);
}
else if (childNodes[i].nodeType == Node.ELEMENT_NODE) {
Array.prototype.push.apply(childTextNodes, getTextNodes(childNodes[i]));
}
}
return childTextNodes;
}
/**
* given a text node, wrap each character in the
* given tag.
*/
function wrapEachCharacter(textNode, tag) {
var text = textNode.nodeValue;
var parent = textNode.parentNode;
var characters = text.split('');
characters.forEach(function(character) {
var element = document.createElement(tag);
var characterNode = document.createTextNode(character);
element.appendChild(characterNode);
parent.insertBefore(element, textNode);
});
parent.removeChild(textNode);
}
现在给出一些HTML,我们将创建它的DOM表示,然后使用第一个函数getTextNodes
从中检索所有文本节点。一旦我们拥有了所有文本节点,我们就可以将它们中的每一个传递给第二个函数 - wrapEachCharacter
。
// create a wrapper element that will hold our HTML.
var container = document.createElement('div');
container.innerHTML = "To Sherlock Holmes she is always <i>THE</i> woman.";
// get all text nodes recursively.
var allTextNodes = getTextNodes(container);
// wrap each character in each text node thus gathered.
allTextNodes.forEach(function(textNode) {
wrapEachCharacter(textNode, 'span');
});
发布了一个示例here。
答案 1 :(得分:3)
沿着这条线的东西应该可以做到这一点
txt = txt.replace (/(<.*?>)|(.)/g, function (m0, tag, ch) {
return tag || ('<span>' + ch + '</span>');
});
答案 2 :(得分:1)
不要使用正则表达式,只需使用for循环遍历字符串:
var s = 'To Sherlock Holmes she is always <i>THE</i> woman.';
var out = '';
for (var z = 0; z < s.length; ++z) {
var ch = s.charAt(z);
if (ch == '<') {
while (ch != '>') {
out += ch;
ch = s.charAt(++z);
}
out += ch;
continue;
}
out += '<span>' + ch + '</span>';
}
alert(out);