Question

现在我正在尝试使用swift 4打印以下星形图案。

为此我采取了以下方法。

for i in stride(from: 1, to: 5, by: 1) {
   // prints from 1 to 4
    for j in stride(from: 1, to: i, by: 1) {
          print(j, separator: "", terminator: "")
    }
    print("*\n")
}

但是现在这将打印在输出之下。

*

1*

12*

123*

有什么方法可以解决这个问题？

Answer 1

1) Pyramid

                *
               * *
              * * *
             * * * *
            * * * * *

LINK :- 

https://replit.com/@vishakhaagarwa1/DarkorchidSmoothPayware#main.swift

for i in 1...5
{
    for _ in stride(from: 5, to: i, by: -1) 
    {
        print(terminator : " ")
    }

    for _ in 1...i
    {
        print("*",terminator : " ")
    }
    print(" ")
}





2) Right Triangle
*
* *
* * *
* * * *
* * * * *

LINK :- 

https://replit.com/@vishakhaagarwa1/StingyOldApplicationstack#main.swift

var i = 1
var j = 1
for i in i...5
{
  for _ in j...i
  {
     print("*",terminator : "")
  }
  print("")
}



3) Mirrored Right Triangle

        *
      * *
    * * *
  * * * *
* * * * *
LINK :- 

https://replit.com/@vishakhaagarwa1/CookedParallelRobodoc#main.swift

for i in 1...5
{
   for _ in stride (from: 5, to: i, by: -1)
  {
    print(" ",terminator : "")
  }
  for _ in 1...i
  {
     print("*",terminator : "")
  }
 
  print("")
}


4) Diamond

        *
      * * *
    * * * * *
  * * * * * * *
* * * * * * * * *
  * * * * * * *
    * * * * *
      * * *
        *

LINK :-

https://replit.com/@vishakhaagarwa1/WarmEmptyDegrees#main.swift






for i in 1...10
{
  if i % 2 != 0
  {
    for _ in stride(from: 10, to: i, by: -1) 
    {
        print(terminator : " ")
    }

    for _ in 1...i
    {
        print("*",terminator : " ")
    }
    print(" ")
  }
}
for i in stride(from: 10, to: 1, by: -1)
{
   if i % 2 != 0
  {
    for _ in stride(from: 10, to: i-1, by: -1) 
    {
        print(terminator : " ")
    }

    for _ in stride(from: 2, to: i, by: 1)
    {
        print("*",terminator : " ")
    }
    print(" ")
  }
}





5) Downward Triangle
* * * * *
* * * *
* * *
* *
*

LINK :- 

https://replit.com/@vishakhaagarwa1/FearlessIndolentByte#main.swift

for i in 1...5
{
  for _ in stride(from: i, to: 6, by: 1)
  {
    print("*",terminator : "")
  }
  print("")
}


6) Right Pascal’s Triangle
*
* *
* * *
* * * *
* * * * *
* * * *
* * *
* *
*
LINK :-

https://replit.com/@vishakhaagarwa1/IndianredNervousPrinter#main.swift

for i in 1...5
{
  for _ in 1...i
  {
     print("*",terminator : "")
  }
 
  print("")
}
for i in 1...4
{
  for _ in stride (from: 5, to: i, by: -1)
  {
     print("*",terminator : "")
  }

  print("")
}


7) Sandglass Pattern

* * * * *
 * * * *
  * * *
   * *
    *
    *
   * *
  * * *
 * * * *
* * * * *

LINK :-

https://replit.com/@vishakhaagarwa1/TangibleDeeppinkWatch#main.swift

for i in 1...5
{
  for _ in 1...i
  {
    print(terminator: " ")
  }
  for _ in stride(from: i, to: 6, by: 1)
  {
    print("*",terminator : " ")
  }
  print("")
}
for i in 1...5
{
    for _ in stride(from: 6, to: i, by: -1) 
    {
        print(terminator : " ")
    }

    for _ in 1...i
    {
        print("*",terminator : " ")
    }
    print(" ")
}

Answer 2

如果你想要

1
12
123
1234

for i in 1..<5 { // or for i in stride(from: 1, to: 5, by: 1) {
    for j in 1...i { // for j in stride(from: 1, through: i, by: 1) {
        print(j, terminator: "")
    }
    print("")
}

如果你想要

*
**
***
****

for i in 1..<5 {
    for _ in 1...i {
        print("*", terminator: "")
    }
    print("")
}

Answer 3

以下是一些快速的逻辑模式，

['PN', 'P/N', 'PN:', 'P/N:']

Answer 4

var q : String = ""
repeat
{
  print("***** Numerical Patterns *****")
  print("1 for Number Right Triangle.. ")
  print("2 for Sequential Number Right Triangle.. ")
  print("3 for Pascal Number Triangle.. ")
  print("Enter Your Choice :: ")
  guard let index = Int(readLine()!), index > 0 && index < 4 else
  {
    print(" !!!! WArning :: Wrong Selection.......")
    print("\n")
    continue
  } 
  var n: Int
  print("Enter N Number For Pattern :: ")
  let num = readLine()
  if let t2 = Int(num!)
  {
    n = t2
  }
  else
  {
    print("wrong input ! taking default [5]")
    n = 5
  }

  switch index {
    case 1  :
        for i in 1...n
        {
          for j in 1...i
          {
            print(j,terminator: " ")
          }
          print("")
        }
    case 2  :
      var j = 0
      for i in 1...n
      {
        for _ in 1...i
        {
          j = j+1
          print(j,terminator: " ")
        }
        print("")
      }
    case 3  :
        for i in 1...n
      { 
        //print("i==",i)
        for _ in stride(from: n, to: i, by: -1) 
        {
          //print("k==",k)
          print(terminator : " ")
        }
        var no = 1
        for j in 1...i
        {
          //print("j==",j)
          print(no,terminator : " ")
          no = no * (i - j) / (j)

        }
        print(" ")
      }
    default :
        print( "Wrong Input............")
  }
  print("\n")
  print("Do you want to continues [PRESS Y/y] OR CLOSE [PRESS N/n] :: ")
  q = (readLine()!)
  print("\n")
}while(q == "y" || q == "Y")

Answer 5

<块引用>

1.  Pyramid

    1 
   1 2 
  1 2 3 
 1 2 3 4 

for i in 1...4{     
    for _ in 1...5-i{
        print(terminator:" ")
    }
    for j in 1...i{
        print(j,terminator:" ")
    }
    print("")
}

2. Inverted Pyramid

 1 2 3 4 
  1 2 3 
   1 2 
    1 

for i in 1...4{   
    for _ in 1...i{
        print(terminator:" ")
    }
   
    for j in 1...5-i{
        print(j,terminator:" ")
    }
    print("")
}

使用步幅功能在swift中打印星形图案

5 个答案: