我想使用assertj来检查包含其他数组的数组中的数据。
accounts: [class AccountResource {
resourceId: 010001781LV
bicFi: null
accountId: null
name: Livret A Rosalie
details: LIVRET A
linkedAccount: null
usage: PRIV
cashAccountType: null
product: LVA
currency: EUR
balances: [class BalanceResource {
name: null
balanceAmount: class AmountType {
currency: EUR
amount: 10000
}
balanceType: CLBD
lastChangeDateTime: null
referenceDate: 2018-05-31
lastCommittedTransaction: null
}, class BalanceResource {
name: null
balanceAmount: class AmountType {
currency: EUR
amount: 10000
}
balanceType: XPCD
lastChangeDateTime: null
referenceDate: 2018-05-31
lastCommittedTransaction: null
}]
psuStatus: Account Holder
links: null
}
我的2个第一次测试案例没问题。我过滤了' resourceId = 010001781LV'我检查account.currency = EUR。我过滤了' resourceId = 010001781LV'我检查了account.balances.size()= 2。
assertThat(halAccounts.getAccounts())
.filteredOn(account -> account.getResourceId().equals("010001781LV"))
.extracting(account -> account.getCurrency())
.containsExactly("EUR");
assertThat(halAccounts.getAccounts())
.filteredOn(account -> account.getResourceId().equals("010001781LV"))
.extracting(account -> account.getBalances().size())
.containsExactly(2);
但我希望过滤' resourceId = 010001781LV'过滤'余额(foreach).balanceType = CLBD'并检查balanceAmount = 10000。
我在其他lambda 中尝试 lambda,但我需要一些帮助:
assertThat(halAccounts.getAccounts())
.filteredOn(account -> account.getResourceId().equals("010001781LV"))
.filteredOn(account -> account.getBalances().forEach(balance -> {
balance.getBalanceAmount().getAmount().equals("10000");
}))
.extracting(balance -> balance.getBalanceAmount().getAmount())
.contains("1000");
我在第二个filteredOn
上遇到此错误:
Multiple markers at this line
- The target type of this expression must be a functional interface
- The method filteredOn(Condition<? super AccountResource>) in the type AbstractIterableAssert<ListAssert<AccountResource>,List<?
extends AccountResource>,AccountResource,ObjectAssert<AccountResource>> is not applicable for the arguments ((<no type> account) -> {})
答案 0 :(得分:1)
重点是filterOn
内的表达式应返回boolean
,而forEach
返回void
。
帐户ID应为&#34; DEF&#34;和所有&#34; A&#34;余额应该有&#34; 10&#34;值。
@Test
void test() {
Account wrongAcc = new Account("ABC", Collections.emptyList());
Account goodAcc = new Account("DEF", Arrays.asList(
new Balance("A", "10"),
new Balance("A", "10"),
new Balance("B", "20")
));
Account wrongBalanceAcc = new Account("DEF", Arrays.asList(
new Balance("A", "10"),
new Balance("A", "20"),
new Balance("B", "20")
));
List<Account> accountList = Arrays.asList(wrongAcc, goodAcc, wrongBalanceAcc);
assertThat(accountList)
.filteredOn(acc -> acc.getId().equals("DEF"))
.filteredOn(acc ->
acc.getBalances()
.stream()
.noneMatch(balance -> balance.getType().equals("A") && !balance.getAmount().equals("10"))
).containsExactly(goodAcc);
}
答案 1 :(得分:0)
如果我是正确的,以下代码不会返回布尔值(forEach不会):
account.getBalances().forEach(balance -> {
balance.getBalanceAmount().getAmount().equals("10000");
})
表示它不是
中使用的有效Predicate
filteredOn(account -> account.getBalances().forEach(balance -> {
balance.getBalanceAmount().getAmount().equals("10000");
}))
我相信java会尝试应用filteredOn(Condition)
这是不可能的。
修改强>
如果您的问题是如何过滤帐户havinn 所有他们的余额等于10000?那么你可以使用这个Predicate
(未经测试,但应该足够接近你想要的):
account -> account.getBalances().stream()
.map(balance -> balance.getBalanceAmount().getAmount())
.allMatch(amount -> amount.equals("10000"))