我有两个型号Permit&场。
class Permit(models.Model):
name = models.CharField(max_length=50)
skill_course = models.ManyToManyField(Skill, related_name="+", blank=True)
class Course(models.Model):
name = models.CharField(max_length=50)
skills = models.ManyToManyField(Skill, related_name="courses",blank=True,)
students = models.ManyToManyField(User, related_name="courses",blank=True,)
单击许可对象将显示动态获取许可的学生(在使用GET方法的UpdateView中)。
如何与这些学生一起创建课程?(在使用POST方法的CreateView中)
我是否必须在2个视图之间传递数据?我想创建一个utils.py文件,创建一个方法,我将在其他方法或类中重用数据,但类或函数将有request
和pk
,我不知道如何返回一个字典,因为它应该有请求和模板对吗?我被困在这里,非常感谢任何帮助,提前谢谢......
答案 0 :(得分:0)
首先,您应该在setting.py
中激活session middleware。
然后使用这样的东西:
def update_project_filter(request):
...
selected_project_id = project_form.cleaned_data["Project_Name"].id
request.session['selected_project_id'] = selected_project_id
...
def update_project(request):
...
selected_project_id = request.session.get('selected_project_id')
...def update_project_filter(request):
...
selected_project_id = project_form.cleaned_data["Project_Name"].id
request.session['selected_project_id'] = selected_project_id
...
def update_project(request):
...
selected_project_id = request.session.get('selected_project_id')
...