Question

我正在尝试使用import matplotlib.pyplot as plt plt.plot(y,'o');plt.plot(res.fun+y);plt.plot(res.fun)在kotlin中使用kotlin.concurrency.thread启动一个新线程但是我一直在：

 Unresolved reference: thread

我以为这是在标准库中？

实际代码：

fun identify(userId: Integer) {
    thread() {
      CustomExceptionHandler(context)
      DoStuffClass.doStuff(context, userId)
    }
  }

Answer 1

正确的导入语句是：

import kotlin.concurrent

示例代码应为：

fun identify(userId: Integer) {
    thread {
        CustomExceptionHandler(context)
        DoStuffClass.doStuff(context, userId)
    }
}

因为thread函数的定义为：

/**
 * Creates a thread that runs the specified [block] of code.
 *
 * @param start if `true`, the thread is immediately started.
 * @param isDaemon if `true`, the thread is created as a daemon thread. The Java Virtual Machine exits when
 * the only threads running are all daemon threads.
 * @param contextClassLoader the class loader to use for loading classes and resources in this thread.
 * @param name the name of the thread.
 * @param priority the priority of the thread.
 */
public fun thread(
    start: Boolean = true,
    isDaemon: Boolean = false,
    contextClassLoader: ClassLoader? = null,
    name: String? = null,
    priority: Int = -1,
    block: () -> Unit
): Thread {
    ...
}

如here所述，thread函数使用lambda作为最后一个参数，然后，根据Kotlin语法，单个参数函数不需要括号，只需要lambda块即可。

未解决的参考线程

1 个答案: