Question

我正在尝试实现一个简单的Pygame脚本，该脚本应该是：

首先，检查用户何时按下 Space 键;
在 Space 按键上，显示一些文字;然后
暂停2秒，然后将屏幕更新为原始状态。

请注意，上述所有事件必须顺序，不能无序。

我遇到问题，程序首先暂停，然后显示文本仅在屏幕更新到其原始状态之前瞬间显示（或根本不显示）。

该程序似乎已跳过步骤2，并在显示文本之前继续执行步骤3中的暂停。我的代码如下：

import pygame
import sys
from pygame.locals import *

WHITE = (255, 255, 255)
BLACK = (0, 0, 0)

pygame.init()
wS = pygame.display.set_mode((500, 500), 0, 32)


# Method works as intended by itself
def create_text(x, y, phrase, color):
    """
    Create and displays text onto the globally-defined `wS` Surface
    (params in docstring omitted)
    """
    # Assume that the font file exists and is successfully found
    font_obj = pygame.font.Font("./roboto_mono.ttf", 32)
    text_surface_obj = font_obj.render(phrase, True, color)
    text_rect_obj = text_surface_obj.get_rect()
    text_rect_obj.center = (x, y)
    wS.blit(text_surface_obj, text_rect_obj)


while True:
    wS.fill(BLACK)
    for event in pygame.event.get():
        if event.type == KEYDOWN and event.key == K_SPACE:

            # Snippet containing unexpected behavior
            create_text(250, 250, "Hello world!", WHITE)
            pygame.display.update()
            pygame.time.delay(2000)
            # Snippet end

        if event.type == QUIT:
            pygame.quit()
            sys.exit(0)
    pygame.display.update()

提前致谢！

Answer 1

由于某种原因，程序对我有用，唯一改变的是字体。这与@ Omega0x013的操作相同，但是帧速率不受限制。之所以有效，是因为 FPS.tick()返回自上次调用以来的时间，如果您未指定帧速率，则它将不保存该程序。

import pygame
import sys
from pygame.locals import *
displayText = False
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)

pygame.init()
wS = pygame.display.set_mode((500, 500), 0, 32)


# Method works as intended by itself
def create_text(x, y, phrase, color):
    """
    Create and displays text onto the globally-defined `wS` Surface
    (params in docstring omitted)
    """
    # Assume that the font file exists and is successfully found

    font_obj = pygame.font.Font(None,30)
    text_surface_obj = font_obj.render(phrase, True, color)
    text_rect_obj = text_surface_obj.get_rect()
    text_rect_obj.center = (x, y)
    wS.blit(text_surface_obj, text_rect_obj)

FPS = pygame.time.Clock()
while True:
    wS.fill(BLACK)
    for event in pygame.event.get():
        if event.type == KEYDOWN and event.key == K_SPACE:
            totalTime = 0
            FPS.tick()
            displayText = True

        if event.type == QUIT:
            pygame.quit()
            sys.exit(0)
    if displayText:
        totalTime += FPS.tick()
        create_text(250, 250, "Hello world!", WHITE)
        if totalTime >= 2000:
            displayText = False
    pygame.display.update()

Answer 2

您应该尝试以下操作：

import pygame
import sys
from pygame.locals import *

WHITE = (255, 255, 255)
BLACK = (0, 0, 0)

pygame.init()
wS = pygame.display.set_mode((500, 500), 0, 32)
clock = pygame.time.Clock()

showing = False
timer = 0
# Method works as intended by itself
def create_text(x, y, phrase, color):
    """
    Create and displays text onto the globally-defined `wS` Surface
    (params in docstring omitted)
    """
    # Assume that the font file exists and is successfully found
    font_obj = pygame.font.Font("./roboto_mono.ttf", 32)
    text_surface_obj = font_obj.render(phrase, True, color)
    text_rect_obj = text_surface_obj.get_rect()
    text_rect_obj.center = (x, y)
    wS.blit(text_surface_obj, text_rect_obj)


while True:
    wS.fill(BLACK)
    for event in pygame.event.get():
        if event.type == KEYDOWN and event.key == K_SPACE:
            showing = True
            timer = 0

        if event.type == QUIT:
            pygame.quit()
            sys.exit(0)

    if showing:
        timer += 1
        create_text(250, 250, "Hello world!", WHITE)

    if timer == 20:
        timer = 0
        showing = False

    pygame.display.update()
    clock.tick(100)

这是每次您按空格键时都会显示文本2秒钟，计数2000毫秒然后不显示。

Pygame Surface非顺序更新

2 个答案: