Question

我试图在2个型号之间引用外键。但是我收到了这个错误：

throw new Error(this.name + '.hasMany called with something that\'s not a subclass of Sequelize.Model'); ^

错误：user_relation.hasMany调用的东西不是Sequelize.Model的子类

squelize.js

const Sequelize = require('sequelize');
const config = require('./default.config')
const sequelize = new Sequelize(config.database, config.user, config.password, {
  host: config.host,
  port: config.port,
  dialect: 'mysql',
  timezone: config.timezone,//东八区
  pool: {
    max: 5,
    min: 0,
    acquire: 30000,
    idle: 10000
  }
});

sequelize
  .sync()
  .then(err => {
    console.log('Connection has been established successfully.');
  })
  .catch(err => {
    console.error('Unable to connect to the database:', err);
  });

module.exports = sequelize;

用户模型

const sequelize = require（＆＃39; sequelize＆＃39;）; const Model = require（＆＃39; ../../ config / squelize＆＃39;）;

const Admin = Model.define('admin', {
  username : {type : sequelize.STRING, allowNull : false},//用户名
  password : {type : sequelize.STRING, allowNull : false},//密码
  details : {type : sequelize.STRING, allowNull : true},//简介
  head_thumb : {type : sequelize.STRING, allowNull : true},//头像
  gender : {type : sequelize.STRING, allowNull : true},//性别
  nickname : {type : sequelize.STRING, allowNull : true},//昵称
  userid : {type : sequelize.INTEGER, autoIncrement : true, primaryKey : true}//用户userid
}, {
  freezeTableName:true
})

module.exports = Admin;

admin_relation.js

var Sequelize = require('sequelize');
const Model = require('../../config/squelize');
const Admin = require('./admin.model')

var user_relation = Model.define('user_relation', {
    id : {type : Sequelize.INTEGER, autoIncrement : true, primaryKey : true},
    userid : {type : Sequelize.STRING, allowNull : false},//用户id
    frendid : {type : Sequelize.STRING, allowNull : false}//朋友id
},{
    timestamps:false,
    freezeTableName:true,
});
user_relation.hasMany(Admin,{as:'admin',foreignKey:'userid'})

module.exports = user_relation;

是否有人看到过这样的错误？我搜索了几天没有任何问题，如果有人可以帮助我真的很感激，

谢谢！

Answer 1

我认为您正在尝试在Adminty模型中的userid键的user_relation模型中维护外键。如果是这样，则必须关联定义sourceKey和targetKey。

使用相同的数据类型定义sourceKey和targetKey。

在管理模式中

Admin.belongsTo(user_relation, {
    foreignKey: 'userid',
    targetKey: 'userid'
});

在user_relation模型中

user_relation.hasMany(Admin, {
    as: 'admin',
    foreignKey: 'userid',
    sourceKey: 'userid'
});

Answer 2

如果存在许多场景，最好创建一个新模型，并在该模型中添加关系。否则，将关系放在一侧。

Admin.belongsTo(User);

在管理员方面，您也可以放置

User.hasMany(Admin);

.hasMany称之为“Sequelize.Model”的子类

2 个答案: