红宝石中的对称阵列

Question

我有这个数组：

flowers = [0, 1, 2, 3, 4, 5, 0, 7, 3, 4]

用户输入示例k=5。我想得到像这样的Symmetry数组：

[0, 7, 3, 4 , 0, 7, 3, 4]

enter image description here

这是我的尝试：

flowers = [0, 1, 2, 3, 4, 5, 0, 7, 3, 4]

print flowers
puts " "
puts "What Is Number Of K ?"
k = gets.to_i
flowers.delete_at(k)
print flowers
n = flowers.count
puts flowers.count
for i in flowers do
  if ((flowers.values_at(n - 1)) == (flowers.values_at(k - 1)))
    puts "yyyyyyyyyyyy"
    k -= 1
    n -= 1
  else
    flowers.delete_at(k)
    puts "nnnnnnnnnnnn"
    # flowers.drop(i)
    k -= 1
    n -= 1
  end
end
puts "Done!"
print flowers

有任何帮助吗？我怎么能这样做？

Answer 1

Date