我有2张表comments
| votes
the `votes` structure
[`id` | `user_id` | `comment_id` | `rating`]
并且评论将comment_id作为主要的确定? 现在我想根据评级总和获得最高评价
[评分为0或1]
我也希望得到顶级用户
答案 0 :(得分:2)
热门评论
这假设注释表有一个名为comments_id的列 SELECT A. * FROM comments INNER JOIN(SELECT comment_id,SUM(rating)汇总FROM投票GROUP BY comment_id)B USING(comment_id)ORDER BY B.sumrating;
这假设注释表有一个名为id
的列
SELECT A. * FROM comments INNER JOIN(SELECT comment_id,SUM(rating)汇总FROM投票GROUP BY comment_id)B ON A.id = B.comment_id ORDER BY B.sumrating;
热门用户
这假设users表有一个名为user_id的列 SELECT A. * FROM users INNER JOIN(SELECT user_id,SUM(rating)汇总FROM投票GROUP BY user_id)B USING(user_id)ORDER BY B.sumrating;
这假设users表有一个名为id的列 SELECT A. * FROM users INNER JOIN(SELECT user_id,SUM(rating)汇总FROM投票GROUP BY user_id)B ON A.id = B.user_id ORDER BY B.sumrating;
热门用户和评论
这假设注释表有一个名为comments_id的列,而用户有一个名为user_id的列 SELECT B. *,C。* FROM (SELECT comment_id,user_id,SUM(rating)汇总FROM投票GROUP BY comment_id,user_id)A 评论B,用户C, 在哪里A.commentment_id = B.comment_id AND A.user_id = C.user_id ORDER BY A.sumrating,C.user_id,B.comment_id;
试一试!!!