我使用curl
测试用户帐户创建API,如下所示:
curl -s -X POST "https://$APISERVER/users" \
-H 'Content-Type: application/json' \
-d '{ \
"username": "'$NEWUSERNAME'", \
"firstName": "'$NEWUSERFIRSTNAME'", \
"lastName": "'$NEWUSERLASTNAME'", \
"displayName": "'$NEWUSERDISPLAYNAME'", \
"password": "'$NEWUSERPASSWORD'" \
}'
并且变量通过命令行参数提供:
APISERVER=http://localhost:8080
NEWUSERNAME=$1
NEWUSERPASSWORD=$2
NEWUSERFIRSTNAME=$3
NEWUSERLASTNAME=$4
# Calculated variable
NEWUSERDISPLAYNAME="${NEWUSERFIRSTNAME} ${NEWUSERLASTNAME}"
脚本的示例调用如下:./test-new-user.sh jdoe Hello123 John Doe
,产生以下变量值:
NEWUSERNAME=jdoe
NEWUSERPASSWORD=Hello123
NEWUSERFIRSTNAME=John
NEWUSERLASTNAME=Doe
(我打算将NEWUSERDISPLAYNAME
设置为“John Doe”)
但我从服务器返回异常,因为curl
命令中的有效负载似乎被切断,不完整或格式错误。
JSON parse error: Unexpected end-of-input in VALUE_STRING\n at [Source:
java.io.PushbackInputStream@2eda6052; line: 1, column: 293]; nested
exception is com.fasterxml.jackson.databind.JsonMappingException:
Unexpected end-of-input in VALUE_STRING\n at [Source:
java.io.PushbackInputStream@2eda6052; line: 1, column: 293]\n at
[Source: java.io.PushbackInputStream@2eda6052; line: 1, column: 142]
(through reference chain:
com.mycompany.api.pojos.NewUser[\"displayName\"])"
如果我在上面的curl命令中硬编码displayName
的值(如下所示),则用户创建请求会完成并完美运行。
"displayName": "John Doe", \
我怀疑它与displayName
中的空格有关,以及我如何使用displayName
插入"'$NEWUSERDISPLAYNAME'"
的值。有没有一种安全的方法在curl
命令的POST请求有效负载中执行变量替换?
答案 0 :(得分:3)
您需要引用shell变量:
printf
为避免过多引用,请尝试以下printf -v json -- '{ "username": "%s", "firstName": "%s", "lastName": "%s", "displayName": "%s", "password": "%s" }' \
"$NEWUSERNAME" "$NEWUSERFIRSTNAME" "$NEWUSERLASTNAME" "$NEWUSERDISPLAYNAME" "$NEWUSERPASSWORD"
curl -s -X POST "https://$APISERVER/users" \
-H 'Content-Type: application/json' \
-d "$json"
:
using (var workbook = new XLWorkbook())
{
workbook.Properties.Author = "Me";
workbook.Properties.Title = "Title";
var worksheet = workbook.AddWorksheet("Sheet 1");
worksheet.Row(1).Cell(1).SetValue("test");
workbook.SaveAs("c:\\temp\\testing.xlsx");
}