我收到了两个指向下面脚本的错误:
收到错误:
无法隐式转换类型'string'
System.Collections.Generic.IEnumerable<Xrm.ActivityParty>
FOR To = emailData.To,
还收到错误:
无法使用集合初始化类型'Xrm.ActivityParty' 初始化程序因为它没有实现 'System.Collections.IEnumerable'FOR From = new ActivityParty {
以下是代码:
foreach (var file in unReadFiles)
{
Microsoft.Office.Interop.Outlook._MailItem emailData = oApp.Session.OpenSharedItem(file);
try
{
Email scrapedMessage = new Email
{
Subject = emailData.Subject,
Subcategory = EmailHelper.ScrapeMethod.Manual.ToString(),
Description = emailData.HTMLBody,
To = emailData.To,
From = new ActivityParty{
emailData.Sender.Address
}
};
}
}
答案 0 :(得分:1)
似乎To
是IEnumerab<ActivityParty>
,您正试图为其分配一个简单的字符串。你可以使用这样的数组:
To = new [] {new ActivityParty { To= emailData.To }}
同样对于From
属性,您需要声明属性名称:
From = new ActivityParty
{
Address = emailData.Sender.Address
}
答案 1 :(得分:0)
根据MSDN文档,您需要创建活动方类变量以指定“收件人”和“发件人”属性。
private Guid _contactId;
private Guid _userId;
// Create the 'From:' activity party for the email
ActivityParty fromParty = new ActivityParty
{
PartyId = new EntityReference(SystemUser.EntityLogicalName, _userId)
};
// Create the 'To:' activity party for the email
ActivityParty toParty = new ActivityParty
{
PartyId = new EntityReference(Contact.EntityLogicalName, _contactId)
};
To = new ActivityParty[] { toParty },
From = new ActivityParty[] { fromParty },