Question

如何将此代码的输出定向到.txt文件？

#include <iostream>
#include <vector>
#include <string>
#include <fstream>

using namespace std;

int main() {

    using std::cin;
    using std::cout;
    using std::endl;

    int input=1; 
    int sum=0; 
    int counter=1;

    while (input != 0) 
    {
        std::cout << "Please enter the hit data: "; 
        std::cin >> input; 

        if (input == 0) // after puting in data input zero 
        {
            break;
        }
        else if (input != 0)
        {
            sum += input; 
            counter++; 
        }
    }
    counter = counter - 1 ; 
    std::cout << "Sum of hits entered: " << sum << endl ; 
    std::cout << "Number of hits entered: " << counter << endl ;

    if ( counter < 100 ) 
    {
        std::cout << "The hits are less than 100" ;
    }
    else if ( counter > 100 ) 
    {
        std::cout << "The hits are greater than 100" ;
    }
    else if ( counter == 100 ) 
    {
        std::cout << "The hits are equal to 100" ;
    }
}

此外，我不是要让用户输入数据，而是如何让程序从另一个.txt文件中读取数据？我知道你可以在终端轻松完成这一切;但是，我希望程序能够创建.txt文件。

另外，如何让程序识别某些数字？我希望它输出类似＆＃34的内容;有12个数字-11计数＆＃34;。

Answer 1

使用std::ifstream读取文件中的输入，使用std::ofstream将输出写入文件。例如：

#include <iostream>
#include <fstream>

int main()
{
    int sum = 0; 
    int counter = 0;

    std::ifstream in("hits.txt");
    if (in.is_open())
    {
        while (in >> input)
        {
            sum += input; 
            ++counter;
        }
    }
    else
    {
        std::ofstream out("hits.txt");
        int input;

        do
        {
            std::cout << "Please enter the hit data: "; 

            // after putting in data, input zero 
            if (!(std::cin >> input) || (input == 0))
                break; 

            out << input << " ";

            sum += input; 
            ++counter;
        }
        while (true);
    }

    std::cout << "Sum of hits entered: " << sum << endl ; 
    std::cout << "Number of hits entered: " << counter << endl ;

    if (counter < 100)
    {
        std::cout << "The hits are less than 100" << std::endl;
    }
    else if (counter > 100) 
    {
        std::cout << "The hits are greater than 100" << std::endl;
    }
    else
    {
        std::cout << "The hits are equal to 100" << std::endl;
    }

    return 0;
}

另外，如何让程序识别某些数字？我希望它输出类似＆＃34的内容;有12个数字-11计数＆＃34;。

您可以使用std:map，例如：

#include <iostream>
#include <fstream>
#include <map>

int main()
{
    int sum = 0; 
    int counter = 0;
    std::map<int, int> hits; // hit counter

    std::ifstream in("hits.txt");
    if (in.is_open())
    {
        while (in >> input)
        {
            hits[input]++;
            sum += input; 
            ++counter;
        }
    }
    else
    {
        std::ofstream out("hits.txt");
        int input;

        do
        {
            std::cout << "Please enter the hit data: "; 

            // after putting in data, input zero 
            if (!(std::cin >> input) || (input == 0))
                break; 

            out << input << " ";

            hits[input]++;
            sum += input; 
            ++counter;
        }
        while (true);
    }

    std::cout << "Sum of hits entered: " << sum << endl ; 
    std::cout << "Number of hits entered: " << counter << endl ;

    if (counter < 100)
    {
        std::cout << "The hits are less than 100" << std::endl;
    }
    else if (counter > 100) 
    {
        std::cout << "The hits are greater than 100" << std::endl;
    }
    else
    {
        std::cout << "The hits are equal to 100" << std::endl;
    }

    for (auto &p : hits)
    {
        if (p.second == 1)
            std::cout << "there was 1 number " << p.first << " counted" << std:::endl;
        else
            std::cout << "there were " << p.second << " number " << p.first << "'s counted" << std:::endl;
    }

    /* or, if you are not using C++11 or later:

    for (std::map<int, int>::iterator iter = hits.begin(); iter != hits.end(); ++iter)
    {
        std::map<int, int>::value_type &p = *iter;

        if (p.second == 1)
            std::cout << "there was 1 number " << p.first << " counted" << std:::endl;
        else
            std::cout << "there were " << p.second << " number " << p.first << "'s counted" << std:::endl;
    }
    */

    return 0;
}

Answer 2

将数据输出到.txt文件确实很容易。您已经包含了，现在需要从std :: ofstream类型创建一个对象，并使用它将文本写入文件。我会创建一个这样的函数（主要）：

#include <iostream>
#include <fstream>
#include <string>

void outputTextToFile (std::string p_text) {
//is created under your project filepath:
  std::ofstream file("nameoffile.txt", std::ios::app); //"app" = appending, instead of overwriting text
  file << "Writing this to a file.\n";
  file.close();
}

之后你可以使用你想要的字符串文本在while循环中调用你的函数，例如：

outputTextToFile("test Text");

从.txt文件中读取文本与此非常相似，我建议你查看这个帖子：Read file line by line

在C ++中将输出定向到.txt文件

2 个答案: