Question

所以，我是Android工作室的初学者，并尝试制作这个简单的应用程序，计算您总共饮用多少水。这个想法是，有人每周都会输入他们喝多少水。当我点击＆＃34;计算它＆＃34;计算一天的总数和平均值。

我的问题是每当我输入一个像小数点2,3的数字应用程序崩溃。我确实找到了一个解决方案，我需要进行验证（if，else）功能，但我不太确定如何在一个函数中选择所有日期。

public class MainActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Button addBtn = (Button) findViewById(R.id.calculateBtn);
        addBtn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                EditText editTextMon = (EditText) findViewById(R.id.editTextMon);
                EditText editTextTue = (EditText) findViewById(R.id.editTextTue);
                EditText editTextWed = (EditText) findViewById(R.id.editTextWed);
                EditText editTextThu = (EditText) findViewById(R.id.editTextThu);
                EditText editTextFri = (EditText) findViewById(R.id.editTextFri);
                EditText editTextSat = (EditText) findViewById(R.id.editTextSat);
                EditText editTextSun = (EditText) findViewById(R.id.editTextSun);
                TextView resultTextView = (TextView) findViewById(R.id.resultTextView);
                TextView errorView = (TextView) findViewById(R.id.errorView);
                TextView averageTextView = (TextView) findViewById(R.id.averageTextView);
                EditText allDays = (EditText) findViewById(R.id.editTextMon); 

                int mon = Integer.parseInt(editTextMon.getText().toString());
                int tue = Integer.parseInt(editTextTue.getText().toString());
                int wed = Integer.parseInt(editTextWed.getText().toString());
                int thu = Integer.parseInt(editTextThu.getText().toString());
                int fri = Integer.parseInt(editTextFri.getText().toString());
                int sat = Integer.parseInt(editTextSat.getText().toString());
                int sun = Integer.parseInt(editTextSun.getText().toString());

                if ( ! (allDays.equals("") || allDays.equals("-")) ) {
                    int result = mon + tue + wed + thu + fri + sat + sun;
                    resultTextView.setText("Total: " + result + " L");

                    int average = result / 7;
                    averageTextView.setText("Avg: " + average + " L");
                } else {
                    errorView.setText("Invalid Input");
                }

            }
        });
    }
}

Answer 1

您正在以float数据类型存储所有值。使用Float.parseFloat(yourEditText.getText().toString());存储它们并使用content = "Example content" filename = "example-file-name". response = HttpResponse(content=content, content_type='text/plain') response['Content-Disposition'] = 'attachment; filename={0}'.format(filename) return response

解析它们

Answer 2

在这种情况下，您可以使用Float x = Float.parseFloat(y);

十进制输入崩溃

2 个答案: