Question

我设置了一个按钮来处理组合框中的两种可能性，这样如果选择了事件1，它将保存到第1到第4行，它可以正常工作并且保存没有问题但是当选择事件2时它应该保存5到8但是它没有正常工作5将把自己置于校正的线上，但是6会像10行一样下降，我昨天花了很多时间来添加和删除代码但是没有任何金牌。

def saveteam():
    with open("data/tournamentdatae1.txt",'r') as f:
        get_all=f.readlines()
        event = combo_event.get()
    if event == 'Event 1':
        with open("data/tournamentdatae1.txt",'r+') as f:
            for i,line in enumerate(get_all,1):         
                if i == 1:                 
                    input1 = team_1.get()
                    f.writelines(input1)
                    f.writelines("\n")
            for i,line in enumerate(get_all,1):         
                if i == 2:                 
                    input2 = team_2.get()
                    f.writelines(input2)
                    f.writelines("\n")
            for i,line in enumerate(get_all,1):         
                if i == 3:                 
                    input3 = team_3.get()
                    f.writelines(input3)
                    f.writelines("\n")
            for i,line in enumerate(get_all,1):         
                if i == 4:                 
                    input4 = team_4.get()
                    f.writelines(input4)
                    f.writelines("\n")
    if event == 'Event 2':
        with open("data/tournamentdatae1.txt",'r+') as f:
            for i,line in enumerate(get_all,1):         
                if i == 5:                 
                    input1 = team_1.get()
                    f.writelines(input1)
                    f.writelines("\n")
                else:
                    f.writelines(line)
            for i,line in enumerate(get_all,1):         
                if i == 6:                 
                    input2 = team_2.get()
                    f.writelines(input2)
                    f.writelines("\n")
                else:
                    f.writelines(line)

这是我的工作，但不知道如何使用此

进行演出

         if event == 'Event 1':
      if indivcombo == 'Individual 1':
          get_all[20] = individual.get() + "\n"
      if indivcombo == 'Individual 2':
          get_all[21] = individual.get() + "\n"
      if indivcombo == 'Individual 3':
          get_all[22] = individual.get() + "\n"
      if indivcombo == 'Individual 4':
          get_all[23] = individual.get() + "\n"
      if indivcombo == 'Individual 5':
          get_all[24] = individual.get() + "\n"
      if indivcombo == 'Individual 6':
          get_all[25] = individual.get() + "\n"
      if indivcombo == 'Individual 7':
          get_all[26] = individual.get() + "\n"
      if indivcombo == 'Individual 8':
          get_all[27] = individual.get() + "\n"
      if indivcombo == 'Individual 9':
          get_all[28] = individual.get() + "\n"
      if indivcombo == 'Individual 10':
          get_all[29] = individual.get() + "\n"
      if indivcombo == 'Individual 11':
          get_all[30] = individual.get() + "\n"
      if indivcombo == 'Individual 12':
          get_all[31] = individual.get() + "\n"
      if indivcombo == 'Individual 13':
          get_all[32] = individual.get() + "\n"
      if indivcombo == 'Individual 14':
          get_all[33] = individual.get() + "\n"
      if indivcombo == 'Individual 15':
          get_all[34] = individual.get() + "\n"
      if indivcombo == 'Individual 16':
          get_all[35] = individual.get() + "\n"
      if indivcombo == 'Individual 17':
          get_all[36] = individual.get() + "\n"
      if indivcombo == 'Individual 18':
          get_all[37] = individual.get() + "\n"
      if indivcombo == 'Individual 19':
          get_all[38] = individual.get() + "\n"
      if indivcombo == 'Individual 20':
          get_all[39] = individual.get() + "\n"
 if event == 'Event 2':
      if indivcombo == 'Individual 1':
          get_all[40] = individual.get() + "\n"
      if indivcombo == 'Individual 2':
          get_all[41] = individual.get() + "\n"

Answer 1

如果我理解正确（大的话），那么你想用team_X变量中的值替换文件中的某些行。你这样做，你把整个文件读到get_all（一个不再连接到文件的列表），然后以r+模式重新打开文件，然后迭代该列表（但不是文件！）直到你得到你要覆盖的行，然后写入新打开的文件。

这应该不起作用，因为新打开的文件仍然在第一行，即使您循环列表也是如此。

相反，我建议直接在列表中替换值，并使用'w'覆盖整个文件。

def saveteam():
    filename = "data/tournamentdatae1.txt"
    with open(filename, 'r') as f:
        get_all = f.readlines()

    event = combo_event.get()
    if event == 'Event 1':
        get_all[0] = team_1.get() + "\n"
        get_all[1] = team_2.get() + "\n"
        get_all[2] = team_3.get() + "\n"
        get_all[3] = team_4.get() + "\n"

    if event == 'Event 2':    
        get_all[4] = team_1.get() + "\n"
        get_all[5] = team_2.get() + "\n"
        get_all[6] = team_3.get() + "\n"
        get_all[7] = team_4.get() + "\n"            

    with open(filename, 'w') as f:
        for line in get_all:
            f.write(line)

您可以通过将要替换的行和相应的团队变量放入列表和列表的dict，然后压缩和进行压缩来进一步减少代码重复（特别是如果有更多＆＃34;事件＆＃34;像这些）循环这些列表：

def saveteam():
    filename = "data/tournamentdatae1.txt"
    with open(filename, 'r') as f:
        get_all = f.readlines()

    team_vars = [team_1, team_2, team_3, team_4]    
    lines = {"Event 1": [0, 1, 2, 3], "Event 2": [4, 5, 6, 7]}

    event = combo_event.get()
    for team, line in zip(team_vars, lines.get(event, [])):
        get_all[line] = team.get() + "\n"

    with open(filename, 'w') as f:
        for line in get_all:
            f.write(line)

注意：我没有测试任何一个。

通过文件阅读团队的分析。（注意：我移动了列表并从方法中删除了它，因为它始终是相同的，这样它可以重复用于读写团队。）

team_vars = [team_1, team_2, team_3, team_4]    
lines = {"Event 1": [0, 1, 2, 3], "Event 2": [4, 5, 6, 7]}
filename = "data/tournamentdatae1.txt"

def showteam():
    with open(filename, 'r') as f:
        get_all = f.readlines()

    event = combo_event.get()
    for team, line in zip(team_vars, lines.get(event, [])):
        team.set(get_all[line].strip())

我需要助手，一个按钮应该可以从具有特定线条的组合框中工作两种可能性，但只适用于选项1

1 个答案: