Question

我有一个列表，其中包含大量网址，数千个网址。这是示例

UrlList = ["www.test.com", "www.123.com", "www.youtube.com", "youtube.com", 123.com, test.com, c.microsoft.com, office.microsoft.com]

有网址没有.com或www。或http：//或https：//并且有哪些。

我试图忽略所有这些，只是在URL List中搜索test或youtube或microsoft等，一旦发现它打印整个URL。

我该怎么做？

编辑：对不起，我忘了张贴尝试 尝试1＃： 尝试代码1＃：

fileURLs = urlReader()
print("Here is the URLs in the File which needs to be search in the List.")
print(fileURLs)
for x in data:
    for y in x['urls']:
        url = str(y)
        if url in fileURLs:
            print(x['id'] , url)

尝试输出1＃：

Here is the URLs in the File which needs to be search in the List
['youtube.com', 'test.com', '123.com']
(u'CUSTOM_03', 'test.com')
(u'CUSTOM_05', 'youtube.com')
(u'CUSTOM_07', 'test.com')
(u'CUSTOM_07', 'youtube.com')
(u'CUSTOM_08', 'youtube.com')
(u'CUSTOM_15', 'test.com')
(u'CUSTOM_16', 'test.com')
(u'CUSTOM_17', 'test.com')
(u'CUSTOM_18', 'test.com')
(u'CUSTOM_19', 'test.com')
(u'CUSTOM_20', 'youtube.com')
(u'CUSTOM_23', 'test.com')
(u'CUSTOM_24', 'youtube.com')

尝试代码2＃：

for x in data :
    for s in x['urls']:
        url = str(s)
        matching = [y for y in fileURLs if url in y]
        if (matching):
            print(x['id'], x['configuredName'], matching)

尝试输出2＃：

Here is the URLs in the File which needs to be search in the List.
['www.youtube.com', 'www.test.com', 'www.123.com']
(u'CUSTOM_03', ['www.test.com'])
(u'CUSTOM_03', ['www.test.com'])
(u'CUSTOM_05', ['www.youtube.com'])
(u'CUSTOM_07', ['www.test.com'])
(u'CUSTOM_07', ['www.youtube.com'])
(u'CUSTOM_08', ['www.youtube.com'])
(u'CUSTOM_10', ['www.youtube.com'])
(u'CUSTOM_15', ['www.test.com'])
(u'CUSTOM_16', ['www.test.com'])
(u'CUSTOM_17', ['www.test.com'])
(u'CUSTOM_18', ['www.test.com'])
(u'CUSTOM_19', ['www.test.com'])
(u'CUSTOM_20', ['www.youtube.com'])
(u'CUSTOM_22', ['www.test.com'])
(u'CUSTOM_23', ['www.test.com'])
(u'CUSTOM_24', ['www.test.com'])
(u'CUSTOM_24', ['www.youtube.com'])
(u'CUSTOM_02', ['www.test.com'])
(u'CUSTOM_02', ['www.123.com'])

查看两次尝试之间的区别，我更改了FileURL From：FileURL = ['youtube.com', 'test.com', '123.com'] 到FileURL = ['www.youtube.com', 'www.test.com', 'www.123.com']

在输出中添加两个新条目：

(u'CUSTOM_02', ['www.test.com'])
(u'CUSTOM_02', ['www.123.com'])

Answer 1

for i in urllist:
    if 'microsoft' in i:
        print(i)

Answer 2

这，使用简单的列表理解来完成任务：

UrlList = ["www.test.com", "www.123.com", "www.youtube.com", "youtube.com", "123.com", "test.com", "c.microsoft.com", "office.microsoft.com"]
searcher = [i for i in UrlList if "www.test.com" in i] 
print(searcher)

Python - 搜索列表中的字符串

2 个答案: