Question

我有一个文件，如下：

the 1 file is:
none
the 2 file is:
a-h-f
the 3 file is:
a-h-p
the 4 file is:
none

我想使用python知道哪两个连续文件是争用的，而不是无。以此文件为例，＆＃34; 2文件＆＃34;和＆＃34; 3档＆＃34;是持续的，有内容。我期待的结果是：

   the 2 file is:
   a-h-f
   the 3 file is:
   a-h-p

请有人给我一些提示。谢谢。

Answer 1

将您的行放在列表中，即lines = f.readlines() f是文件对象，或者：

lines = '''the 1 file is:
none
the 2 file is:
a-h-f
the 3 file is:
a-h-p
the 4 file is:
none
'''.splitlines()

然后：

for t in zip(*[lines[i::2] for i in range(4)]):
    if 'none' not in t:
        # t is ('the 2 file is:', 'a-h-f', 'the 3 file is:', 'a-h-p')
        # do something with it, e.g.:
        for x in t:
            print(x)

打印：

the 2 file is:
a-h-f
the 3 file is:
a-h-p

Answer 2

列出4个连续元素并过滤掉没有元素的元素。派对......

with open("input_file","r") as in_file:
    lines = in_file.read().split("\n")
consecutive_lines_4 = [lines[i:i+4] for i in range(0,len(lines)-3),2]
result = [i for i in consecutive_lines_4 if 'none' not in i]
print(result)

如何使用python查找连续的行

2 个答案: