如何存储＆＃39;计数＆＃39;的输出？变成一个列表？ （蟒蛇）

Question

当你看到变量＆＃39; count＆＃39;初始值为0.这会在循环运行时被另一个值覆盖;我们可以说新值是＆＃39; 8＆＃39;。然后当循环再次运行时，新值为＆＃39; 8＆＃39;被新的价值所覆盖;我们可以说新值是＆＃39; 5＆＃39;。这意味着价值＆＃39; 8＆＃39;是不可恢复的。我不想丢失从循环中创建的任何值，而是将它们存储到列表中。如何将创建的值存储到列表中？

这是我的代码：

def printTable(items):
    for i in  range (len(items[0])):
        print ()
        counter = 0
        for j in range(len(items)):
            if len(items[i][j]) > counter:                count = len(items[i][j])
                itemName = items[i][j]
        print ('the longest string is: ' + itemName + '; and its length is ' + str(counter))            

tableData = [['apples','oranges','cherries','banana'],
             ['Alice','Bob','Carol','David'],
             ['dogs','cats','moose','goose']]

printTable(tableData)

Answer 1

创建一个列表，然后在每次循环运行时将count的值附加到它。

def printTable(items):
    count_list = []
    for i in  range (len(items[0])):
        print ()
        counter = 0
        for j in range(len(items)):
            if len(items[i][j]) > counter:
            count = len(items[i][j])
            count_list.append(count)
            itemName = items[i][j]
        print ('the longest string is: ' + itemName + '; and its length is ' + str(counter))
    return count_list            

tableData = [['apples','oranges','cherries','banana'],
             ['Alice','Bob','Carol','David'],
             ['dogs','cats','moose','goose']]

printTable(tableData)