Question

我打算将spark数据帧保存到hive表中，这样我就可以查询它们并从中提取纬度和经度，因为Spark数据帧不可迭代。

使用jupyter中的pyspark，我编写了这段代码来制作一个火花会话：

import findspark
findspark.init()
from pyspark import SparkContext, SparkConf
from pyspark.sql import SparkSession

#readmultiple csv with pyspark
 spark = SparkSession \
.builder \
.appName("Python Spark SQL basic example") \
.config("spark.sql.catalogImplementation=hive").enableHiveSupport() \
.getOrCreate()

 df = spark.read.csv("Desktop/train/train.csv",header=True);

 Pickup_locations=df.select("pickup_datetime","Pickup_latitude",
                          "Pickup_longitude")

 print(Pickup_locations.count())

然后我运行hiveql：

df.createOrReplaceTempView("mytempTable") 
spark.sql("create table hive_table as select * from mytempTable");

我得到了这个错误：

 Py4JJavaError: An error occurred while calling o24.sql.
 : org.apache.spark.sql.AnalysisException: Hive support is required to      CREATE Hive TABLE (AS SELECT);;
 'CreateTable `hive_table`,    org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe, ErrorIfExists
+- Project [id#311, vendor_id#312, pickup_datetime#313,    dropoff_datetime#314, passenger_count#315, pickup_longitude#316,     pickup_latitude#317, dropoff_longitude#318, dropoff_latitude#319,     store_and_fwd_flag#320, trip_duration#321]

Answer 1

我以前处于这种情况。您需要将配置参数传递给spark-submit命令，以便它将hive视为spark sql的目录实现。

以下是Spark提交的外观：

spark-submit --deploy-mode cluster --master yarn --conf spark.sql.catalogImplementation=hive  --class harri_sparkStreaming.com_spark_streaming.App  ./target/com-spark-streaming-2.3.0-jar-with-dependencies.jar

诀窍在：--conf spark.sql.catalogImplementation=hive

希望这会有所帮助

CREATE Hive TABLE（AS SELECT）需要Hive支持

1 个答案: