Question

我正在寻找C＃或VB.net的答案。

我得到一个这样的字符串：

{"1":{"pump":1,"name":"Pump 1","type":"VS","time":"2:10 PM","run":10,"mode":0,"drivestate":0,"watts":1656,"rpm":2850,"gpm":0,"ppc":0,"err":0,"timer":1,"duration":"durationnotset","currentrunning":{"mode":"off","value":0,"remainingduration":-1},"externalProgram":{"1":-1,"2":-1,"3":-1,"4":-1},"remotecontrol":1,"power":1,"friendlyName":"Pump 1"},"2":{"pump":2,"name":"Pump 2","type":"None","time":"timenotset","run":"runnotset","mode":"modenotset","drivestate":"drivestatenotset","watts":"wattsnotset","rpm":"rpmnotset","gpm":"gpmnotset","ppc":"ppcnotset","err":"errnotset","timer":"timernotset","duration":"durationnotset","currentrunning":{"mode":"off","value":0,"remainingduration":-1},"externalProgram":{"1":-1,"2":-1,"3":-1,"4":-1},"remotecontrol":"remotecontrolnotset","power":"powernotset","friendlyName":"Pump 2"}}

所以，只有两个记录。我只需要从每个中提取“名称”，“瓦特”和“转速”。我不需要将整个记录存储在数组或列表中，因为我只是处理行。

我该怎么做？

Answer 1

您可以使用Newtonsoft.Json执行此操作，只需在Nuget上找到它。

你可以像这样使用它，虽然它有点脏......

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System.IO;

namespace ConsoleApp1
{
    class Program
    {
        static void Main(string[] args)
        {
            string json = File.ReadAllText("TextFile1.txt");
            JObject jsonObject= (JsonConvert.DeserializeObject(json) as JObject);
            string name = jsonObject.Value<JObject>("1").Value<string>("name");
        }
    }
}

我在TextFile1中用你的json字符串测试它，它运行良好。你最好为它做一个自定义类型反序列化。

关键部分是JsonConvert.DeserializeObject(json)，它将json字符串转换为CLR对象，即JObject。然后是.Value<JObject>("1")位，它只是使用了newtonsoft api。

P.S。我注意到你有一个json.net标签，他们的网站几乎说：https://www.newtonsoft.com/json

使用Newtonsoft.Json迭代多个记录

1 个答案: