Question

我有这个数组：

[ [ '2018-05-28T21:51:00Z',
    0.00000858,
    0.00000857,
    0.00000860,
    0.00000855,
    12511.81490226 ],
  [ '2018-05-28T21:52:00Z',
    0.00000853,
    0.00000850,
    0.00000856,
    0.00000847,
    12687.20140187 ],
  [ '2018-05-28T21:53:00Z',
    0.00000848,
    0.00000847,
    0.00000850,
    0.00000846,
    12708.9320888 ]
]

我需要将其转换为：

{ 
    T: [ '2018-05-28T21:51:00Z', '2018-05-28T21:52:00Z', '2018-05-28T21:53:00Z' ],
    O: [ 0.00000858, 0.00000853, 0.00000848],
    C: [ 0.00000857, 0.00000850, 0.00000847],
    H: [ 0.00000860, 0.00000856, 0.00000850],
    L: [ 0.00000855, 0.00000847, 0.00000846],
    V: [ 12511.81490226, 12687.20140187, 12708.9320888 ]
}

它是预定义的地方，第一个值始终是＆＃39; T＆＃39;第二个值始终是＆＃39; O＆＃39;等等。

尝试像这样的lodash

_.zipObject(['T', 'O', 'H', 'L', 'C'], s.values)

但结果不是预期的。一些建议？

Answer 1

不需要库，您可以使用普通的Javascript轻松完成此任务：

const input=[['2018-05-28T21:51:00Z',0.00000858,0.00000857,0.00000860,0.00000855,12511.81490226],['2018-05-28T21:52:00Z',0.00000853,0.00000850,0.00000856,0.00000847,12687.20140187],['2018-05-28T21:53:00Z',0.00000848,0.00000847,0.00000850,0.00000846,12708.9320888]]
const keys = ['T', 'O', 'C', 'H', 'L', 'V'];
const arrs = input.reduce((accum, item) => {
  keys.forEach((key, i) => accum[key].push(item[i]));
  return accum;
}, keys.reduce((a, key) => { a[key] = []; return a }, {}));
console.log(arrs);

Answer 2

你可以通过使用zip和zipobject来实现：

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/1.2.1/lodash.min.js"></script>

＆＃13;

{{1}}

＆＃13;

Answer 3

您可以通过以下方式实现此目的：

const trans  = data[0].map((col, i) => data.map(row => row[i]));

_.zipObject(['T', 'O', 'H', 'L', 'C'], trans)

数据是您的初始数组。

使用lodash将数组映射到对象

3 个答案: