我有一个我正在解析的xml文件。虽然有些标签名称碰巧多次发生,但在不同的父名下。我知道哪个父母的孩子我想忽略。我怎样才能做到这一点?
<sub-article id="S01" article-type="translation" xml:lang="pt">
<front-stub>
<article-categories>
<subj-group subj-group-type="heading">
<subject>Artigos Originais</subject>
</subj-group>
</article-categories>
<title-group>
<article-title>
Prevalência de deficiência nutricional em pacientes com
tuberculose pulmonar
<xref ref-type="fn" rid="fn02">*</xref>
</article-title>
</title-group>
</front-stub>
</article-categories>
</sub-article>
.....
.....
<article-meta>
<article-id pub-id-type="pmid">24068270</article-id>
<article-id pub-id-type="pmc">4075858</article-id>
<article-id pub-id-type="publisher-id">S1806-37132013000400012</article-id>
<article-id pub-id-type="doi">10.1590/S1806-37132013000400012</article-id>
<article-categories>
<subj-group subj-group-type="heading">
<subject>Original Articles</subject>
</subj-group>
</article-categories>
<title-group>
<article-title>
Prevalence of nutritional deficiency in patients with
pulmonary tuberculosis
<xref ref-type="fn" rid="fn01">*</xref>
</article-title>
</title-group>
<article-meta>
在此示例中,我不想处理子文章标记下的子项。因此,“文章标题”仅针对“肺结核患者营养缺乏的患病率”进行处理,而不是“Prevalênciadeinfeiêncianutricionalem pacientes com tuberculose pulmonar”
我目前正在关注代码,该代码返回名称为“title-group”的所有节点。如何使其具体化,以便我不会从某个父级获取它。
NodeList titleNodeList = document.getElementsByTagName("title-group");
答案 0 :(得分:1)
只需在“子文章”节点下搜索“title-group”节点:
List<Node> allTitleGroupNodes = new ArrayList<>();
NodeList subArticleNodes = document.getElementsByTagName("sub-article");
for (int i = 0; i < subArticleNodes.getLength(); i++) {
NodeList titleNodes = subArticleNodes.item(i).getElementsByTagName("title-group");
for (int j = 0; j < titleNodes.getLength(); j++) {
allTitleGroupNodes.add(titleNodes.item(j));
}
}
(旁白:NodeList
的可怕界面是我最讨厌在标准Java中处理XML的事情之一。)
答案 1 :(得分:1)
使用XPath有两种方法可以实现它:
<article-meta>
<sub-article>
我个人更喜欢第一个,因为它更明确,并且始终面向不同的XML文件。
使用XPath仅选择<article-meta>
下的元素:
//article-meta//title-group
爪哇:
XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xPath.compile("//article-meta//title-group");
NodeList titleNodes = (NodeList) expr.evaluate(document, XPathConstants.NODESET);
如果元素位于<sub-article>
下,请使用XPath排除元素。我假设XML根元素是<article>
(如果不是这样的话,请证明代码的合理性):
/article/*[not(self::sub-article)]//title-group
爪哇
XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xPath.compile("/article/*[not(self::sub-article)]//title-group");
NodeList titleNodes = (NodeList) expr.evaluate(document, XPathConstants.NODESET);