我的网站中有两种类型的用户。管理员和用户。
这些文件以user的名称存储在表格kind中。
有了这个，我可以验证登录会话：
<body>
<?php if(isset($_SESSION["user_id"])):?>
<div class="wrapper">
<div class="sidebar" data-color="blue">
<div class="logo">
<a href="./" class="simple-text">
INDEX PAGE FOR BOTH ADMINS AND USERS
</a>
</div>
<div class="sidebar-wrapper">
<ul class="nav">
<li class="">
<a href="./">
<i class="fa fa-home"></i>
<p>Home</p>
</a>
</li>
<li>
<a href="./?view=tickets">
<i class="fa fa-ticket"></i>
<p>Tickets</p>
</a>
</li>
<li>
<a href="./?view=calendario">
<i class="fa fa-ticket"></i>
<p>Calendar</p>
</a>
</li>
<li>
<a href="./?view=projects">
<i class="fa fa-building"></i>
<p>Projects</p>
</a>
</li>
<li>
<a href="./?view=categories">
<i class="fa fa-th-list"></i>
<p>Categories</p>
</a>
</li>
<li>
<a href="./?view=reports">
<i class="fa fa-area-chart"></i>
<p>Reports</p>
</a>
</li>
<li>
<a href="./?view=users">
<i class="fa fa-users"></i>
<p>Users</p>
</a>
</li>
</ul>
</div>
</div>
<div class="main-panel">
<nav class="navbar navbar-transparent navbar-absolute">
<div class="container-fluid">
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" href="./"><b>Desktop IT Manager</b></a>
</div>
<div class="collapse navbar-collapse">
<ul class="nav navbar-nav navbar-right">
<li class="dropdown">
<a href="#" class="dropdown-toggle" data-toggle="dropdown">
<i class="fa fa-user"></i>
<?php echo Core::$user->name." ".Core::$user->lastname." ".Core::$user->kind; ?>
</a>
<ul class="dropdown-menu">
<li class="divider"></li>
<li><a href="./?view=configuration">Account Settings</a></li>
<li class="divider"></li>
<li><a href="logout.php">Logout</a></li>
</ul>
</li>
</ul>
<!--
<form class="navbar-form navbar-right" role="search">
<div class="form-group is-empty">
<input type="text" class="form-control" placeholder="Search">
<span class="material-input"></span>
</div>
<button type="submit" class="btn btn-white btn-round btn-just-icon">
<i class="fa fa-search"></i><div class="ripple-container"></div>
</button>
</form>
-->
</div>
</div>
</nav>
<div class="content">
<div class="container-fluid">
<?php
View::load("login");
?>
</div>
</div>
<footer class="footer">
<div class="container-fluid">
<nav class="pull-left">
<ul>
<li>
</li>
<!--
<li>
<a href="#">
Company
</a>
</li>
<li>
<a href="#">
Portfolio
</a>
</li>
<li>
<a href="#">
Blog
</a>
</li>
-->
</ul>
</nav>
<p class="copyright pull-right">
Developed by <a href="http://wwww.iesahn.com" target="_blank">Imagen Electrónica S.A de C.V</a> © <script type="text/javascript">document.write(new Date().getFullYear());</script>
</p>
</div>
</footer>
</div>
</div>
<?php else:?>
<?php
View::load("login");
?>
<?php endif;?>
</body>
使用<?php echo Core::$user->name." ".Core::$user->lastname." ".Core::$user->kind; ?>我从数据库中提取用户的名字和姓氏，并使用Core::$user->kind我提取用户类型。 1表示管理员，2表示用户。
现在，我想按用户类型限制对故障单系统的某些部分的访问。
我有这个想法，至少对于菜单来说：
<?php if(isset($_SESSION["user_id"])):?>
<?php if((<?php echo Core::$user->kind; ?>) == 1):?>
// insert full <div class="wrapper"> here
<?php else:?>
// insert modified <div class="wrapper"> here (limited functions for
// normal users
<?php endif;?>
<?php else:?>
<?php
View::load("login");
?>
<?php endif;?>
但是......它不会起作用。我怎样才能使它发挥作用？
答案 0 :(得分：0)
<?php if(isset($_SESSION["user_id"])):?>
<?php if(Core::$user->kind==1):?>
//Admin Content
<?php elseif(Core::$user->kind==2):?>
//User Content
<?php endif; ?>
<?php else:?>
<?php
View::load("login");
?>
<?php endif;?>
这完美无缺。我将使用此验证票证系统的所有其他部分。