Question

我在实现我想要的输出时遇到了问题。我有一个包含product_id和style_id的表。每个产品包含1种或许多不同的样式。 style_id列不能与任何行相同。

注意我希望通过 SQL 查询或使用 PHP 代码。

product_style

id product_id style_id 1 1 1 2 1 2 3 1 3 4 1 4 5 2 1

我希望通过 SQL查询或使用 PHP代码来实现此结果。

Array[12][ { "id": 1, "name": "Product sample", "description": "Sample", "price": "11.00", "level": "school", "style_name":{[ "Style 1", "Style 2", "Style 3", "Style 4" ] } "style_id": {[ 1, 2, 3, 4, ] }, "rank_id": 232 } { "id": 2, "name": "Sample 2", "description": "Sample 2", "price": "10.00", "level": "school", "style_name": "Karate", "style_id": 1, "rank_id": 232 } ]

这是我目前的代码。

$grading_products= \DB::table('products as p') ->leftjoin('product_style as ps', 'p.id', '=', 'ps.product_id') ->join('style_users as su', 'ps.style_id', '=', 'su.style_id') ->join('styles as s', 'ps.style_id', '=', 's.id') ->whereRaw('su.user_id = ' .$id. ' AND p.product_type_id = 1 AND p.service_sub_type_id = 2') ->select('p.id', 'p.name', 'p.description', 'p.price', 'p.level', 'ps.product_id', 's.name as style_name', 'ps.style_id as ps_style', 'su.style_id', 'su.rank_id') ->get();

这是我当前的输出

Array[12][ { "id": 1, "name": "Product Sample", "description": "Sample", "price": "11.00", "level": "school", "style_name": "style 1", "style_id": 1, "rank_id": 232 }, { "id": 1, "name": "Product Sample", "description": "Sample", "price": "11.00", "level": "school", "style_name": "style 2", "style_id": 2, "rank_id": 232 } { "id": 2, "name": "Sample 2", "description": "Sample 2", "price": "10.00", "level": "school", "style_name": "Karate", "style_id": 1, "rank_id": 232 }, ]

注意我希望通过 SQL 查询或使用 PHP 代码。

Answer 1

使用当前输出作为起点，这是一个混乱的解决方案：

$new_output = [];

$keyed = [];

foreach ($current_output as $row) {
    $keyed[$row['id']]['style_name'][] = $row['style_name'];

    $keyed[$row['id']]['style_id'][] = $row['style_id'];

    $keyed[$row['id']]['row'] = $row;
}

foreach ($keyed as $id => $data) {
    $row = $data['row'];

    $temp_output = [
        'id' => $id,
        'name' => $row['name'],
        'description' => $row['description'],
        'price' => $row['price'],
        'level' => $row['level'],
    ];

    if (count($keyed[$row['id']]['style_name']) > 1) {
        $temp_output['style_name'] = $data['style_name'];
    } else {
        $temp_output['style_name'] = $data['style_name'][0];
    }

    if (count($keyed[$row['id']]['style_id']) > 1) {
        $temp_output['style_id'] = $data['style_id'];
    } else {
        $temp_output['style_id'] = $data['style_id'][0];
    }

    $temp_output['rank_id'] = $row['rank_id'];

    $new_output[] = $temp_output;
}

（未经测试）

使用相同的product_id合并行，但每行使用不同的style_id

1 个答案: