我正在为DataRequest创建扩展以记录事件
func log() -> Self {
let responseSerializer = DataRequest.jsonResponseSerializer(options: .allowFragments)
return response(queue: nil, responseSerializer: responseSerializer) { response in
if let object = response.result.value {
/* do the job */
}
}
}
并收到错误Unable to infer closure type in the current context
由于它具有(DataResponse<T.SerializedObject>) -> Void
泛型类型,有没有办法显式设置类型来修复此错误?
Alamofire版本: 4.7.2 Xcode版本: 9.3 Swift版本: 4 运行Alamofire的平台: 的iOS
答案 0 :(得分:0)
func log() -> Self {
let responseSerializer = DataRequest.jsonResponseSerializer()
return response(responseSerializer: responseSerializer) { [weak self] response in
guard let _self = self else { return }
_self.printRequestString(response)
}
}
效果很好。