我在从前端bootstrap发送json数据到表达servlet时遇到了问题。这是我尝试过的。我使用ajax将数据从我的表单发送到带有json的servlet类。请伸手解决这个问题。我的表格是注册学生:
<html>
<head>
<link rel="stylesheet" type="text/css" href="resources/css/bootstrap.min.css">
<script type="text/javascript" src="resources/js/jquery.min.js"></script>
<script type="text/javascript" src="resources/js/bootstrap.min.js"> </script>
<script type="text/javascript">
function registerStudent() {
var firstName = $("#firstName").val();
var lastname = $("#lastname").val();
var phone = $("#phone").val();
var email = $("#email").val();
var studentCode = $("#studentCode").val();
$.ajax({
type : "POST",
url : "/RegisterStudent",
data :{data: "firstName=" + firstName + "lastname=" + lastname + " phone=" + phone + "email=" + email+"studentCode"+studentCode},
success : function(data) {
var ht = data.msg;
$("#resp").html(ht);
},
error : function(data) {
alert("Some error occured.");
}
});
}
</script>
</head>
<body>
<div class="container">
<div class="card " style="width:750px;margin:0px auto">
<div class="card-header">Student Register</div>
<div class="card-body">
<form data-toggle="validator" role="form" method="post" >
<div class="form-group">
<label class="control-label" for="firstName">Name</label>
<input class="form-control" data-error="Please enter name field." id="firstName" placeholder="Name" type="text" required />
<div class="help-block with-errors"></div>
</div>
<div class="form-group">
<label for="lastname" class="control-label">lastname</label>
<input type="text" class="form-control" id="lastname" placeholder="lastname" required>
<div class="help-block with-errors"></div>
</div>
<div class="form-group">
<label for="phone" class="control-label">phone</label>
<div class="form-group">
<input type="text" data-minlength="5" class="form-control" id="phone" data-error="fill your phone" placeholder="phone" required>
<div class="help-block with-errors"></div>
</div>
</div>
<div class="form-group">
<label class="control-label" for="email">email</label>
<textarea class="form-control" data-error="Please enter email field." id="email" placeholder="email" required=""></textarea>
<div class="help-block with-errors"></div>
</div>
<div class="form-group">
<label for="studentCode" class="control-label">studentCode</label>
<div class="form-group">
<input type="text" class="form-control" id="studentCode" data-error="fill your studentCode" placeholder="studentCode" required>
<div class="help-block with-errors"></div>
</div>
</div>
</form>
</div>
<button onclick="registerStudent();" type="button" class="btn btn-success btn-block">Register</button>
<div class="text-center" id="resp" style="margin-top: 14px;"></div>
</div>
</div>
这是我的servletclass,用于将数据发送到数据库。
@WebServlet(urlPatterns = "/RegisterStudent")
public class RegisterStudentController extends HttpServlet {
StudentServiceInter service = new StudentServiceImpl();
ObjectMapper mapper = new ObjectMapper();
String json = "";
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
Student student = new Student();
req.getSession().setAttribute("student", student);
resp.sendRedirect("/addStudent.jsp");
}
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
String jsonData = req.getParameter("data");
resp.setContentType("application/json");
PrintWriter out = resp.getWriter();
out.println(jsonData);
out.close();
}
}
答案 0 :(得分:0)
一个问题是,客户端,你没有创建json,而服务器端你试图解析json。 Json格式没有//div[@id='rates_detail_desc']/strong[2]
符号。
有效对象是:
equal (=)
在发送之前,您应该data = {
data: {
firstName: 'Name',
lastName: 'Surname',
phone: '123-4456',
email: 'a@b.c',
studentCode: 12345
}
};
。
答案 1 :(得分:0)
试试这个......
$.ajax({
type: 'GET',
url: '<?php echo base_url(); ?>"/RegisterStudent"', // your syntax
data: {
'firstName ': firstName ,
'lastName' :lastname,
'phone': phone,
'email' : email,
'studentCode' : studentCode,
},
success : function(data) {
var ht = data.msg;
$("#resp").html(ht);
},
error : function(data) {
alert("Some error occured.");
}
});