Question

我有一个bash脚本，它有大约2000行代码，在这个脚本的各行中，脚本将一些状态消息写入日志文件，即LogFiles.txt，bills.txt 我想对仅在LogFiles.txt中写入状态消息的所有行进行注释（搜索和替换文本）

示例脚本文件：

echo "+++++++++++++++++++++">>bills.txt
echo "doing some stuff">>bills.txt
echo "starting
to execute some commands">>LogFiles.txt
echo "----------------------">>LogFiles.txt
ls 
cat someFile.txt| grep "search me"
echo "search results found">>LogFiles.txt
echo "----------------------">>LogFiles.txt
echo "+++++++++++++++++++++">>bills.txt
echo "doing some more stuff">>bills.txt
some other commands...
echo "finshing 
script
 execution">>LogFiles.txt
echo "----------------------">>LogFiles.txt

所需的输出：

echo "+++++++++++++++++++++">>bills.txt
echo "doing some stuff">>bills.txt
/*echo "starting
to execute some commands">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
ls 
cat someFile.txt| grep "search me"
/*echo "search results found">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
echo "+++++++++++++++++++++">>bills.txt
echo "doing some more stuff">>bills.txt
some other commands...
/*echo "finshing 
script
 execution">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/

现在我已经使用了以下命令，但结果并不好：

sed -e 's/echo/\/\*echo/gI' -e 's/LogFiles.txt/LogFiles.txt\*\//gI' samplescript.sh

此命令产生的结果：

/*echo "doing some stuff">>bills.txt
/*echo "starting
to execute some commands">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
ls
cat someFile.txt| grep "search me"
/*echo "search results found">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/
some other commands...
/*echo "finshing
script
 execution">>LogFiles.txt*/
/*echo "----------------------">>LogFiles.txt*/

这里出现了问题，当sed -e命令的第一部分用/ * echo替换所有echo时这是一种错误的方法，因为我不需要为bills.txt注释回声。

Answer 1

使用: '和'语法在bash中进行多行注释，如@Aserre指出，使用sed：

sed -r -e "/^echo/ {/>>/ bb; :a; N; />>/! ba; :b; />>LogFiles\.txt/I {s/^echo/: ' echo/; s/(>>.*)$/\1 '/}}" samplescript.sh

还可以使用-i直接在脚本文件上写入。

Sed命令解释：

/^echo/ {              # in a line that starts with 'echo'
  />>/ bb              # if also already contains '>>' jump forward to 'b' label
  :a                   # 'a' label to jump to
  N                    # read next line and add it to pattern space
  />>/! ba             # if pattern space not contains '>>' jump back to 'a' label
  :b                   # 'b' label to jump to
  />>LogFiles\.txt/I { # now if pattern space contains '>>LogFiles.txt' case insensitive
    s/^echo/: ' echo/  # add open comment before 'echo'
    s/(>>.*)$/\1 '/    # add close comment at the end of the line with '>>'
  }
}

Answer 2

以下简单position: absolute可能对您有所帮助。

awk

如果您想将输出存储到Input_file中，请在上面的代码中附加awk '/LogFiles.txt$/{$0="##"$0} 1' Input_file。

解决方案第二： 使用> temp_file && mv temp_file Input_file备份实际的Input_file。

sed

Answer 3

请勿使用注释进行配置。重写您的脚本以允许配置某些块。

: ${LOG_FILE:=LogFile.txt}

{
  echo "+++++++++++++++++++++"
  echo "doing some stuff"
} >> bills.txt

{
  echo "starting
to execute some commands"
  echo "----------------------"
} >> "$LOG_FILE"

ls 
cat someFile.txt| grep "search me"
{
  echo "search results found"
  echo "----------------------"
} >> "$LOG_FILE"
{
  echo "+++++++++++++++++++++"
  echo "doing some more stuff"
} >> bills.txt

some other commands...

{
  echo "finshing 
  script
   execution"
  echo "----------------------"
} >> "$LOG_FILE"

现在，如果要禁用写入日志文件，只需使用

运行脚本即可

LOG_FILE=/dev/null ./sampleScript.sh

而不是评论线。

在字符串中查找模式后评论bash行

3 个答案: