Question

我最近在项目中升级了eclipse和java版本，但发生了一些错误。我尝试重现并发现以下设置导致使用Java 1.8的Eclipse Oxigen.3a（4.7.3a）中的错误，而同样适用于eclipse 3.7.2和Java 1.7

TestSomeObject.java：

package a;
public class TestSomeObject
{
}

TestGeneric.java：

package a;
public class TestGeneric<T>
{
  T element;

  protected class InnerGeneric
  {
     T innerElement;

     public InnerGeneric() { }
  }
}

TestA.java：

package a;

public class TestA extends TestGeneric<TestSomeObject>
{
  public TestA(String a, String b) {}

  public InnerA someMethod(String some, InnerGeneric inner)
  {
     return new InnerA(some, inner);
  }

  protected class InnerA
  {
     public InnerA(String a, InnerGeneric b) {  }
  }
}

TestB.java

package a;
import a.TestA;

public class TestB extends TestA
{
  public TestB(String a, String b){
     super(a,b);
  }

  public InnerA someMethod(String some, InnerGeneric inner)
  {
     return new InnerB(some, inner);
  }

  protected class InnerB extends InnerA
  {
     public InnerB(String a, InnerGeneric b)
     {
        super(a, b);
     }
  }
}

在类测试B中，我收到以下编译错误：

someMethod：Description Resource Path Location Type Name clash: The method someMethod(String, TestGeneric<TestSomeObject>.InnerGeneric) of type TestB has the same erasure as someMethod(String, TestGeneric<TestSomeObject>.InnerGeneric) of type TestA but does not override it TestB.java line 13 Java Problem
在致电超级（a，b）时：Description Resource Path Location Type The constructor TestA.InnerA(String, TestGeneric<TestSomeObject>.InnerGeneric) is undefined TestB.java line 22在此处输入代码Java Problem

在eclipse版本：3.7.2和Java 1.7中，这可行。

为什么？我该怎么做才能清除错误？

Answer 1

答案是，更精确地定义方法签名中的InnerGeneric类：

TestB.java：

package a;

public class TestB extends TestA
{
  public TestB(String a, String b){
     super(a,b);
  }

  public InnerA someMethod(String some, TestGeneric<TestSomeObject>.InnerGeneric inner)
  {
     return new InnerB(some, inner);
  }

  protected class InnerB extends InnerA
  {
     public InnerB(String a, TestGeneric<TestSomeObject>.InnerGeneric b)
     {
        super(a, b);
     }
  }
}

Java - ＆＃39;名称冲突＆＃39;和＆＃39;构造函数undefined＆＃39;覆盖从外部类继承泛型的内部类时出错

1 个答案: