我有一个小的PHP页面,它从MySQL获取数据并通过PHP在月历中显示。我无法在数组中正确排列数据以获得所需的输出。
首先,我将描述我想要发生的事情:
为了在日历上显示这些数据,我使用MySQL从各种来源输出数据,然后使用PHP将其输入到数组中,我按日期和输出进行排序。
我的问题是,我希望每天能够处理多行数据,但由于我使用日期作为密钥,因此我每天仅显示一个结果。如果我使用循环将日期与密钥中的计数器附加在一起,那么在有人进行预订然后在同一天取消该预订的情况下,我会得到重叠结果。
至于我的代码......
首先,我检查学生是否在每周课程中注册,然后将该课程输入数组。
$sql = "SELECT StudentDB.studentid, ClassDB.classID, ClassDB.class_level, ClassDB.class_title, ClassDB.time, ClassDB.teacher, StudentDB.first_name, StudentDB.last_name, StudentDB.payment_amount, ClassDB.day
FROM ClassDB
INNER JOIN RegDB ON ClassDB.classID = RegDB.classid
INNER JOIN StudentDB ON StudentDB.studentID = RegDB.studentid
WHERE StudentDB.studentid = '$studentid'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) { // DISPLAY REGULAR CLASS DATA
$dayofclass = $row['day'];
$class_level = $row['class_level'];
$class_title = $row["class_title"];
$day = $row["day"];
$class_time = $row["class_time"];
$time = $row["time"];
// check which dates match the days of the week and store in an array
for ($i=1;$i<=$n;$i++){
if ($i<10) {
$i = "0" . $i;
}
$day=date("l",strtotime($yearmonth.$i)); //find weekdays
if($day==$dayofclass){
$time = date("H:i",strtotime($row['time']));
$dates[]=$yearmonth.$i;
$datesdata[$yearmonth.$i] = "0";
$timedata[$yearmonth.$i] = $time;
$classiddate[$yearmonth.$i] = $row['classID'];
}
}
}
echo "</table>";
$conn->close();
}
之后,我会检查具体的预订(取消,不定期预订,候补名单)并将其输入数组:
$lowerlimit = $yearmonth . "01";
$upperlimit = $yearmonth . "31";
$sql = "SELECT AttendanceDB.*, ClassDB.*
FROM StudentDB
INNER JOIN AttendanceDB ON StudentDB.studentid = AttendanceDB.studentid
INNER JOIN ClassDB ON AttendanceDB.classid = ClassDB.classID
WHERE StudentDB.studentid = '$studentid'
AND AttendanceDB.class_time >= '$lowerlimit'
AND AttendanceDB.class_time <= '$upperlimit'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
$loopcount = 0;
// store furikae data in the array
while($row = $result->fetch_assoc()) {
$phpdate = strtotime( $row["class_time"] );
$time = date("H:i",strtotime($row['time']));
$mysqldate = date( 'Y-m-d', $phpdate );
$loopcount++;
$mysqldate = $mysqldate . "+" . $loopcount;
// $loopcount++;
// $mysqldate = $mysqldate . "+" . $loopcount;
$previousdate = $mysqldate;
$previousfurikae = $row['furikae'];
if ($row["furikae"] == 3){
$dates[]=$mysqldate;
$datesdata[$mysqldate] = "1";
$timedata[$mysqldate] = $time;
$classiddate[$mysqldate] = $row['classID'];
} elseif ($row["furikae"] == 8 OR $row["furikae"] == 7) {
$dates[]=$mysqldate;
$datesdata[$mysqldate] = "3";
$timedata[$mysqldate] = $time;
} elseif ($row["furikae"] == 2) {
$dates[]=$mysqldate;
$datesdata[$mysqldate] = "2";
$timedata[$mysqldate] = $time;
}
}
}
$conn->close();
然后我最后检查学校日历并输入数组中的日期:
$sql = "SELECT *
FROM SchoolScheduleDB
WHERE date >= '$lowerlimit'
AND date <= '$upperlimit'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// store furikae data in the array
while($row = $result->fetch_assoc()) {
$phpdate = strtotime( $row["date"] );
// $time = date("H:i",strtotime($row['time']));
// $mysqldate = date( 'Y-m-d', $phpdate ) . " " . $time;
$mysqldate = date( 'Y-m-d', $phpdate );
$dates[]=$mysqldate;
$datesdata[$mysqldate] = "666";
}
}
$conn->close();
我打算工作的方式是:
目前,这个功能应该如此,但它仅限于每天显示1个结果,但我希望每天能够为多个班级的学生显示超过1个结果。
感谢您的帮助。如果我在我的问题上犯了任何错误,或者我的问题不明确,我会尽力修改它。
答案 0 :(得分:0)
您可以使用边括号为每个日期创建一个子数组:
$data[20180528][] = 'aa';
$data[20180528][] = 'bb';
$data[20180529][] = 'cc';
$data[20180529][] = 'dd';
$data[20180529][] = 'ee';
会给你一个像这样的数组:
20180528 => aa
=> bb
20180529 => cc
=> dd
=> ee