我有一个JSON对象,如下所示:
{
"name": "cameraasd_main_autofocus",
"value": "Lasasd autofocus",
"displayName": "Autofocus"
},
{
"name": "screen_siasdze",
"value": "5.2\asd",
"displayName": "Sdascreen Size",
"group": "General"
},
{
"name": "camera_maindas_features",
"value": "Digital Zoom,das Auto Flash, Digital image stabilization"
"displayName": "Features"
},
在这个数据对象中,我只想定位具有group
属性ng-repeat
的元素。我必须进一步将这些元素与特定群体分组。例如,从整个对象中,具有组值"General"
的元素应该与其余元素分开。
答案 0 :(得分:1)
<div ng-repeat="x in records">
<div ng-if="x.group"> {{x.name}} </div>
</div>
试试这是否有效!!祝你好运!
答案 1 :(得分:1)
您可以创建范围变量来存储具有属性“group”的已过滤项目,如下所示
var data = [{
"name": "cameraasd_main_autofocus",
"value": "Lasasd autofocus",
"displayName": "Autofocus"
},
{
"name": "screen_siasdze",
"value": "5.2asd",
"displayName": "Sdascreen Size",
"group": "General"
},
{
"name": "camera_maindas_features",
"value": "Digital Zoom,das Auto Flash, Digital image stabilization",
"displayName": "Features"
}];
$scope.filteredData = data.filter(function(x){ return x.hasOwnProperty("group")});
然后在UI中使用ng-repeat
<ul>
<li ng-repeat="item in filteredData">
{{item.name}} || {{item.value}}
</li>
</ul>
以下是工作示例:https://jsfiddle.net/Lt7aP/8267/
修改:如果您想根据特定的组名分离出元素,那么您可以尝试以下代码
$scope.filteredData = data.filter(function(x){ return x.hasOwnProperty("group") && x.group == "General"});
在这种情况下,只会显示General
个组。
答案 2 :(得分:0)
假设您的JSON包含一个数组(在您的json中没有显示但我认为它在那里)。 首先,将JSON解析为JsonObject,然后将其作为数组
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<table class="table" id="data_table">
<tbody>
<tr>
<th></th>
<th></th>
<th></th>
</tr>
<tr class="table">
<td></td>
<td class="prod">First cell</td>
<td class="prod">Second cell</td>
<td class="prod">Third Cell</td>
<td> <button type="button" id="btn1" class="add-row">Replace Row</button></td>
</tr>
<tr class="table_hidden">
<td></td>
<td>1a</td>
<td>2a</td>
<td>3a</td>
<td></td>
</tr>
<tr class="table">
<td></td>
<td class="prod">Fourth Cell</td>
<td class="prod">Fifth cell</td>
<td class="prod">Sixth Cell</td>
<td> <button type="button" id="btn2" class="add-row">Replace Row</button></td>
</tr>
<tr class="table_hidden">
<td></td>
<td>4a</td>
<td>5a</td>
<td>6a</td>
<td></td>
</tr>
<tr class="table">
<td></td>
<td class="prod">Seventh</td>
<td class="prod">Eighth</td>
<td class="prod">Ninth</td>
<td> <button type="button" id="btn3" class="add-row">Replace Row</button></td>
</tr>
<tr class="table_hidden">
<td></td>
<td>7a</td>
<td>8a</td>
<td>9a</td>
<td></td>
</tr>
<tbody>
</table>
</div>
然后你可以在你的html中执行此操作
JSONArray jsonArray = new JSONArray(jsonString);
答案 3 :(得分:0)
检查此代码。
<div>
<h3>With Group</h3>
<div ng-repeat="d in data">
<div ng-if="d.group">
{{d.name}}
</div>
</div>
</div>
<div>
<h3>Without Group</h3>
<div ng-repeat="d in data">
<div ng-if="!d.group">
{{d.name}}
</div>
</div>
</div>