Question

我有一个数据的对象，其中包含每个部分的一些字段，但每个部分的每个条件的某些字段（每个条件的数据都在子类PartData中）：

class Part {
    // per part data
    final String part_number;

    public Part(String part_number) {
        this.part_number = part_number;
        condition_id_to_data = new HashMap<>();
    }

    public String getPart_number() {
        return part_number;
    }

    Map<Integer, PartData> condition_id_to_data;

    public PartData getData(int condition_id) {
        return condition_id_to_data.get(condition_id);
    }

    // per condition data
    class PartData {
        final int condition_id;

        public PartData(int condition_id) {
            this.condition_id = condition_id;
        }

        BigDecimal sales;
        BigDecimal quotes;

        public BigDecimal getQuotes() {
            return quotes;
        }

        public BigDecimal getSales() {
            return sales;
        }
    }
}

我需要编写一个lambda函数，它将在应用part / condition时返回数据：

Function<Part, String> part_number_function;
Function<Part, Function<Integer, BigDecimal>> sales_function;
Function<Part, Function<Integer, BigDecimal>> quotes_function;

void go() {

    Part part = ...;
    int condition_id = ...;

    part_number_function = Part::getPart_number; // Got this part
    String part_number = part_number_function.apply(part); // works


    sales_function = Part::getData ... ?
    quotes_function = Part::getData ... ?

    BigDecimal sales = sales_function.apply(part).apply(condition_id);
    BigDecimal quotes = quotes_function.apply(part).apply(condition_id);
}

如何在lambda函数中应用两个变量？

Answer 1

当我问这个问题时，我搜索了“两个参数java lambda函数”并找到了这个问题：Can a java lambda have more than 1 parameter?

所以，我创建了一个BiFunction类：

@FunctionalInterface
interface BiFunction<One, Two, Three> {
    public Three apply(One one, Two two);
}

这适用于One和Two并返回Three

并编写了这样的方法：

Function<Part, String> part_number_function;
BiFunction<Part, Integer, BigDecimal> sales_function;
BiFunction<Part, Integer, BigDecimal> quotes_function;

void go() {

    Part part = ...;
    int condition_id = ...;

    part_number_function = a_part -> a_part.getPart_number();
    sales_function = (a_part, b_cond) -> a_part.getData(b_cond).sales;
    quotes_function = (a_part, b_cond) -> a_part.getData(b_cond).quotes;

    String part_number = part_number_function.apply(part);
    BigDecimal sales = sales_function.apply(part, condition_id);
    BigDecimal quotes = quotes_function.apply(part, condition_id);
}

这有效

应用嵌套的Lambda函数Java 8

1 个答案: