Question

我在Windows上编写了这段代码并且运行正常，但在Ubuntu中使用g ++我得到了这个错误：

在myList.h中

#ifndef myList
#define myList

#include <iostream>
using namespace std;

class List {
private:
class Node; // Forward declaration
Node *tail;
Node *head;

public:
List();
List(const List &src);
~List();

void newTail(const double num);
void newHead(double num);
void insert(const int pos, const double num);

void print() const;
void printReverse() const;

double popHead();
double popAt(const int pos);

double dataHead() const;
double dataAt(const int pos) const;

bool isEmpty() const;
int size() const;

List& operator = (const List & rhs);
List& operator += (const List & rhs);
};
#endif

在myList.cpp中（不是全部）

#include "myList.h"

class List::Node {
private:
double data;
Node *next;
Node *prev;

public:
friend class List;
Node(Node *argNode, double num) : next(argNode), data(num) // Initilize this node's next pointer to first arg and data to second arg
{
    if (argNode != NULL) // If this node isn't to be head
    {
        this->prev = argNode->prev; // Initilize this node's prev pointer to next's node prev pointer   

        if (argNode->prev != NULL) // If the next node wasn't tail
            argNode->prev->next = this; // Set the next's node's previous node's next pointer to this node

        argNode->prev = this; // Set the next node's prev pointer to this node
    }
}
};

List::List(){}

List::List(const List &list)
{
    *this = list;
}

List::~List()
{
while (tail != NULL)
{
    Node *temp = tail;
    tail = temp->next;
    delete temp;
}

head = NULL;
}
double List::popAt(const int pos)
{
if (pos >= List::size())
    cout << "No node at position: " << pos << endl;

double data = 0;
int nodeCounter = 0;

for (Node *p = tail; p; p = p->next, nodeCounter++)
{
    if (nodeCounter == pos)
    {
        data = p->data;

        if (p == head && p == tail)
        {
            List::~List();
            break;
        }

        if (p != head && p != tail)
        {
            p->prev->next = p->next;
            p->next->prev = p->prev;
            delete p;
            break;
        }

        if (p == tail)
        {
            p->next->prev = NULL;
            tail = p->next;
            delete p;
            break;
        }

        if (p == head)
        {
            p->prev->next = NULL;
            head = p->prev;
            delete p;
            break;
        }
    }
return data;
}

我已经阅读了其他有关此错误的帖子，但他们都没有提到析构函数，我不能因为爱我而理解为什么它不会特别针对Ubuntu。

感谢您的帮助和时间。

Answer 1

正如评论所指出的，调用List :: ~List（）是一个坏主意。

function f(){
 var ar=[],i;
 for(i=0;i<3;i++){
//this time instead of passing i, the funciton has a local value called 
x 

arr[i]=(function(x)){
  return function(){
    return x;
  };
}(i));
}
return arr; 
}

更好的主意。感谢您的所有帮助，我想我得到了应得的待遇。

C ++错误：没有匹配函数用于调用（在Windows中工作，在Ubuntu中出现此错误）

1 个答案: