Angular 6 AngularFireAuth检查用户是否在页面呈现之前登录

时间:2018-05-28 19:45:53

标签: javascript angular typescript firebase firebase-authentication

我已经使用Firebase身份验证和Cloud Fire Store设置了一个新的角度6项目。有一个登录页面,您可以通过谷歌登录,用户数据保存在Firestore中(下面的代码)。我唯一的问题是如何检查用户是否已登录,是否有最佳做法?

目前我正在获取用户数据异步,但导航正在闪烁。一秒钟有登录按钮,然后它切换到注销按钮。在呈现页面之前有没有好的方法来检查登录状态? enter image description here one second later

  

User.ts

export interface User {
  uid: string;
  email: string;
}
  

auth.service.ts

import { Injectable } from '@angular/core';
import { Router } from '@angular/router';
import * as firebase from 'firebase/app';
import { AngularFireAuth } from 'angularfire2/auth';
import { AngularFirestore, AngularFirestoreDocument } from 'angularfire2/firestore';
import { Observable, of } from 'rxjs';
import { switchMap } from 'rxjs/operators';
import { User } from './user';

@Injectable({
  providedIn: 'root'
})
export class AuthService {

  user: Observable<User>;

  constructor(private afAuth: AngularFireAuth, private afs: AngularFirestore, private router: Router) {
    this.user = this.afAuth.authState.pipe(
        switchMap(user => {
          if (user) {
            return this.afs.doc<User>(`users/${user.uid}`).valueChanges();
          } else {
            return of(null);
          }
        }))
  }

  public googleLogin() {
    const provider = new firebase.auth.GoogleAuthProvider()
    return this.oAuthLogin(provider);
  }

  public signOut() {
    this.afAuth.auth.signOut();
  }

  private oAuthLogin(provider) {
    return this.afAuth.auth.signInWithPopup(provider)
      .then((credential) => {
        this.updateUserData(credential.user)
      })
  }

  private updateUserData(user) {
    const userRef: AngularFirestoreDocument<any> = this.afs.doc(`users/${user.uid}`);
    const data: User = {
      uid: user.uid,
      email: user.email
    }
    return userRef.set(data, { merge: true })
  }

}
  

navigation.component.ts

import { Component, OnInit } from '@angular/core';
import { AuthService } from '../core/auth.service';
import { AngularFireAuth } from 'angularfire2/auth';

@Component({
  selector: 'app-navigation',
  templateUrl: './navigation.component.html',
  styleUrls: ['./navigation.component.scss']
})
export class NavigationComponent implements OnInit {

  constructor(public auth: AuthService) { }

  ngOnInit() {}

}

  

auth.service.ts

<div *ngIf="auth.user | async; then loggedIn else loggedOut"></div>

<ng-template #loggedOut>
    <li  class="nav-item d-none d-md-inline-block pl-2 pr-0">
        <a class="btn btn-sm btn-primary u-btn-primary u-btn-pill transition-3d-hover" href="/login">
            Login
        </a>
    </li>
</ng-template>

<ng-template #loggedIn>
    <li  class="nav-item d-none d-md-inline-block pl-2 pr-0">
        <a class="btn btn-sm btn-primary u-btn-primary u-btn-pill transition-3d-hover" (click)="auth.signOut()">
            Logout
        </a>
    </li>
</ng-template>

2 个答案:

答案 0 :(得分:1)

您可能很久以前就想出了这一点,但其他人可能会想知道。我选择对angularFireAuth的authState进行检查。如果为空,则您已注销。然后,您可以按照Ryan Chenkie's Medium article

中的说明使用路由防护
@Injectable()
export class FirebaseAuthService {
private authState: Observable<firebase.User>
private currentUser: firebase.User = null;

constructor(
  public afAuth: AngularFireAuth,
  private http: HttpClient,
  private localStorage: LocalStorageService,
  private router: Router,
  private snackBar: MatSnackBar) {
  this.authState = this.afAuth.authState;

this.authState.subscribe(user => {
  if (user) {
    this.currentUser = user;
    this.localStorage.storeSimple('userData', user)
    this.openSnackBar('Successfully authenticated');
    console.log('AUTHSTATE USER', user)
    this.router.navigate(['home']);
  } else {
    console.log('AUTHSTATE USER EMPTY', user)
    this.currentUser = null;
  }
},
  err => {
    this.openSnackBar(`${err.status} ${err.statusText} (${err.error.message})`, 'Please try again')
  });
 }

 isAuthenticated(): boolean {
   return this.authState !== null;
 }

 loginEmail(email, password, route) {
   this.afAuth.auth.signInWithEmailAndPassword(email, password).catch(error => {
   let errorCode = error.code;
   let errorMessage = error.message;
   this.openSnackBar(error, 'OK')
 });
}

logout() {
  this.afAuth.auth.signOut()
  .then(response => this.openSnackBar('Signed out'))
  .catch(error => this.openSnackBar('Error signing out: ' + error));
}

...
}

答案 1 :(得分:0)

你可以使用can激活路径概念存在于角度的路由模块中......在这个概念中,它只是在每次页面的路由或导航发生时调用可注入服务....在那里你也可以检查用户是否有权查看该页面